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How do you use the word Permutations in a sentence?

"The permutations of meaning in the treaty would all about insure conflict later."


How many ways prioritize four pending jobs from most to least important?

To prioritize four pending jobs from most to least important, you can use permutations, as the order matters. The number of ways to arrange four distinct jobs is calculated as 4!, which equals 24. Therefore, there are 24 different ways to prioritize the four jobs.


How can I efficiently use the np permute function in Python to generate all possible permutations of a given list?

To efficiently use the np permute function in Python to generate all possible permutations of a given list, you can first import the numpy library and then use the np permute function with the list as an argument. This will return an array of all possible permutations of the elements in the list.


How many permutations does the string ABC have?

3x2x1=6 permutations.


How many permutations can you get out of an eight word phrase?

There are 8! = 40320 permutations.


What is the permutations and combinations for the word great?

There are 120 permutations and only 1 combination.


How many permutations in obfuscation?

If you mean permutations of the letters in the word "obfuscation", the answer is 1,814,400.


How many permutations are possible of the letters in the word Fresno?

There are 6! = 720 permutations.


How many permutations are possible of the word information?

39916800 permutations are possible for the word INFORMATION.


How many permutations are in the word arithmetic?

10! permutations of the word "Arithmetic" may be made.


How many 3 letter permutations of the word October?

There are 195 3-letter permutations.


How many distinguishable and indistinguishable permutations are there in the word algrebra?

The word "algrebra" has 8 letters, with the letter 'a' appearing twice and 'r' appearing twice. To find the number of distinguishable permutations, we use the formula for permutations of multiset: ( \frac{n!}{n_1! \times n_2!} ), where ( n ) is the total number of letters and ( n_1, n_2 ) are the frequencies of the repeating letters. Thus, the number of distinguishable permutations is ( \frac{8!}{2! \times 2!} = 10080 ). Since all letters are counted in this formula, there are no indistinguishable permutations in this context.