3d shapes with plane faces are called polyhedra (singular = polyhedron). The minimum number of vertices is 4, there is no maximum.
A cube has 8 vertices and 6 faces. Therefore a cube has 2 more vertices than faces.
The number of vertices does not determine the number of faces. If the shape with 6 vertices was a quadrilateral based bipyramid, it would have 8 faces. A hexagonal based pyramid has 7 vertices and 7 faces. So more vertices does not necessarily imply more faces.
A cube is a geometric shape which has 6 faces and 8 vertices ie .2 more vertices than faces
A tetrahedron (4 triangular faces) is the only polyhedron that has a unique configuration of faces, edges and vertices. For any polyhedron with n (>4) faces, there is a prism with a pair of n-2 sided polygons as bases as well a pyramid whose base is an n-1 sided polygon. There are many other configurations for polyhedra with more faces. For example, there are ten [topologically] different figures with 6 faces: 3 of these are concave polyhedra.
A polyhedron is a generic term for 3 dimensional objects which are bounded by polygonal faces. They can have 4 or more vertices, 6 or more edges and 4 or more faces. The numbers of vertices (V), edges (E) and faces (F) must also satisfy the Euler characteristic: F + V = E + 2.
Oh, dude, it's like a math riddle! So, if a polyhedron has 10 more edges than vertices, we can use Euler's formula: Faces + Vertices - Edges = 2. Since we know the relationship between edges and vertices, we can substitute that in and solve for faces. So, it would have 22 faces. Math can be fun... sometimes.
A shape that has more faces than vertices is a polyhedron. In a polyhedron, the number of faces is always greater than or equal to the number of vertices. For example, a cube has 6 faces and 8 vertices, so it has more faces than vertices.
3d shapes with plane faces are called polyhedra (singular = polyhedron). The minimum number of vertices is 4, there is no maximum.
A cube has 8 vertices and 6 faces. Therefore a cube has 2 more vertices than faces.
The number of vertices does not determine the number of faces. If the shape with 6 vertices was a quadrilateral based bipyramid, it would have 8 faces. A hexagonal based pyramid has 7 vertices and 7 faces. So more vertices does not necessarily imply more faces.
A cube is a geometric shape which has 6 faces and 8 vertices ie .2 more vertices than faces
There are infinitely many polyhedra with one or more triangular faces.
An octahedron, for example. 8 faces, 6 vertices.
A tetrahedron (4 triangular faces) is the only polyhedron that has a unique configuration of faces, edges and vertices. For any polyhedron with n (>4) faces, there is a prism with a pair of n-2 sided polygons as bases as well a pyramid whose base is an n-1 sided polygon. There are many other configurations for polyhedra with more faces. For example, there are ten [topologically] different figures with 6 faces: 3 of these are concave polyhedra.
No. A cube has 6 faces and 8 vertices - it has exactly 2 more vertices than faces.
There are a few families of polyhedra with identical faces. There are none whose faces have 6 or more sides. There is no special name for polyhedra whose faces are pentagons or pentagrams. A dodecahedron is an example. If coplanar faces are disallowed, the only polyhedron with quadrilateral faces are the cube and rhombohedron. There are infinitely many polyhedra with equilateral triangular faces: the tetrahedron, octahedron and icosahedron are examples.