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For all polyhedra:

vertices + faces = edges + 2

The given fact is:

edges = vertices + 10

→ vertices + faces = vertices + 10 + 2

→ faces = 12

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It has 12 faces.

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Q: If a polyhedron has 10 more edges than vertices how many faces does it have?

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Such a polyhedron cannot exist. According to the Euler characteristics, V + F - E = 2, where V = vertices, F = faces, E = edges. This would require that the polyhedron had only two faces.

12 vertices A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges.

3 faces, 2 edges, and no vertices

4 faces, 6 edges, 4 verticesFour faces, six edges and four vertices.

6 faces, 12 edges and 8 vertices.

Related questions

A polyhedron has 30 edges and 12 vertices. How many faces does it have

A sphere is not a polyhedron because it has no edges, no vertices and no flat faces The word 'polyhedron' means many faces.

It is a triangular prism that has 5 faces, 6 vertices and 9 edges

It has 6 vertices.

eight

6

Such a polyhedron cannot exist. According to the Euler characteristics, V + F - E = 2, where V = vertices, F = faces, E = edges. This would require that the polyhedron had only two faces.

12 vertices A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges.

v=60-20

The only thing that can be said that there must be at least 4 faces and at least 6 edges and that the polyhedron must satisfy the Euler criterion which requires that: Faces + Vertices = Edges + 2.

If the object is a convex polyhedron, then, by Euler's characteristics, it should have 23 faces.

The number of vertices and faces is 2 more than the number of Edges according to Euler's formula. So a gemstone with 22 edges must have a total of 24 faces and vertices.