Square side 3cm. Rectangle 2cm x 4cm. Equilateral triangle side 4cm.
1/2*4*3 = 6 square cm
5 cm
It will be a right angle triangle with a base of 3cm, a height of 4cm and a hypotenuse of 5cm
That would have to be cubic cm. 216 of them.
3cm + 4cm + 3cm + 4cm = 14 cm
For it to be a right angle triangle the 3rd side must be 5cm
Square side 3cm. Rectangle 2cm x 4cm. Equilateral triangle side 4cm.
Yes, it is possible to build a triangle with side lengths of 3 cm, 4 cm, and 5 cm. This triangle would be a right triangle, following the Pythagorean theorem which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In this case, 3^2 + 4^2 = 5^2 (9 + 16 = 25), satisfying the condition for a right triangle.
1/2*4*3 = 6 square cm
5 cm
It will be a right angle triangle with a base of 3cm, a height of 4cm and a hypotenuse of 5cm
That would have to be cubic cm. 216 of them.
24 cm3
0 cm, since it is not visible.
120 cm. If you multiply 4 cm times 3cm times 10 cm you will get= 120cm. Volume formula: l*w*h
A scalene triangle