Square side 3cm. Rectangle 2cm x 4cm. Equilateral triangle side 4cm.
1/2*4*3 = 6 square cm
5 cm
It will be a right angle triangle with a base of 3cm, a height of 4cm and a hypotenuse of 5cm
That would have to be cubic cm. 216 of them.
For it to be a right angle triangle the 3rd side must be 5cm
Square side 3cm. Rectangle 2cm x 4cm. Equilateral triangle side 4cm.
1/2*4*3 = 6 square cm
5 cm
It will be a right angle triangle with a base of 3cm, a height of 4cm and a hypotenuse of 5cm
That would have to be cubic cm. 216 of them.
24 cm3
120 cm. If you multiply 4 cm times 3cm times 10 cm you will get= 120cm. Volume formula: l*w*h
0 cm, since it is not visible.
A scalene triangle
The area of the triangle with these sides is found by Heron's formula, which states that: semiperimeter = (a + b + c) / 2 Area = √(s(s - a)(s - b)(s - c)) Then: semiperimeter = (6 + 8 + 4) / 2 cm = 9 cm Area = √(9(9 - 8)(9 - 6)(9 - 4)) cm² ≈ 11.6 cm²
32 x 42 = 25 square root of 25 = 5 The answer is 5 cm.