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It is 8961 - W*int(8961/W)
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
100015
11
27836/56 gives 497 and 4 as quotient and remainder Dividend- remainder =27836-4 = 27832 which is divisible by 56. So the least no that to be subracted is 4
It is 8961 - W*int(8961/W)
It is 20 because 5220/180 = 29
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
9400÷65 gives144 quotient,40 remainder. 65×145 =9425 25 is the least
10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor× quotient so 10056-5=23×437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23×438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23
100015
18 must be subtracted from 5694 to get a number exactly divisible by 43
Oh, isn't that just a happy little math problem we have here? To find the least number to add to 3500 to make it divisible by 42, 49, 56, and 63, we need to find the least common multiple of these numbers. Once we find that, we can subtract 3500 and see the magic number that will make it all work out beautifully. Just a few simple calculations and we'll have our answer in no time!
13801-55 = 13746 and 13746/87 = 158
None. The LCM (least common multiple) is the smallest positive whole number exactly divisible by two or more whole numbers.
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what is the least 5- digit number which is exactly divisible by 36