To find the least number that must be added to 37969 to make it exactly divisible by 65, first, we calculate the remainder when 37969 is divided by 65. The remainder is 44 (since 37969 ÷ 65 = 584 with a remainder of 44). To make it divisible by 65, we need to add (65 - 44 = 21). Thus, the least number that must be added is 21.
It is 8961 - W*int(8961/W)
To find the least number that must be added to 1056 to make it divisible by 23, first, we divide 1056 by 23, which gives us a quotient of 45 with a remainder of 21. Since 1056 is 21 more than a multiple of 23, we need to add ( 23 - 21 = 2 ) to 1056. Therefore, the least number that must be added to 1056 to make it exactly divisible by 23 is 2.
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
Nope - For any number to be divisible by three, the sum of the digits added together must ALSO be divisible by three. In this case 1+4=5.
342 is divisible by 6 and not 5.Numbers divisible by 5 end in zeros or fivesNumbers divisible by 6 have a slightly more complicated rule. If, when the individual digits are added together and they make a multiple of 3, see if the number is even. If so, and the digits add up to a multiple of 3, then the number is a divisible by 6.
339 + 1 = 340,which is exactly divisible.
It is 20 because 5220/180 = 29
It is 8961 - W*int(8961/W)
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
9400÷65 gives144 quotient,40 remainder. 65×145 =9425 25 is the least
10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor× quotient so 10056-5=23×437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23×438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23
Any number ending in 3.
Nope - 1038 is an even number and thus is divisible by 2. Its digits added together total 12 - which is divisible by 3... therefore the original number is also divisible by 3 !!
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
459684/187 give 2458 and 38 as quotient and remainder. Now next possibility 187 *2459 give 459833. 459833-459684 =149 it should be added. 149 is answer
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
To find the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9, we first need to determine the remainder when 2.45 is divided by 9. 2.45 can be written as 245/100. When 245 is divided by 9, the remainder is 8. To make 2.45 exactly divisible by 9, we need to add the difference between 9 and the remainder, which is 9 - 8 = 1. Therefore, the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9 is $0.01.