To find the perimeter of a shape, you simply add up the lengths of all its sides. In this case, the perimeter would be 8cm + 6cm + 2cm + 5cm + 3cm + 8cm, which equals 32cm. So, the perimeter of the shape with sides measuring 8cm, 6cm, 2cm, 5cm, 3cm, and 8cm is 32cm.
The largest angle will be opposite length 8cm and by using the cosine rule it works out as 125.1 degrees rounded to one decimal place
It is sqrt(62 + 102 + 82) = sqrt(200) = 60.53 cm (approx).
Dimensions are given out as length by width 14cm by 1cm 13cm by 2cm 12cm by 3cm 11cm by 4cm 10cm by 5cm 9cm by 6cm 8cm by 7cm And the rest is all repeats of the above.
8cm is about 3 inches
It is: 200/8 = 25
It is impossible to get a triangle with the side lengths 14cm, 3cm and 8cm 14cm itself is larger than the sum of two other lengths (3cm + 8cm = 11cm).
8cm !
The area of a regular hexagon with side lengths of 8cm is about 166.3cm2
The answer is, you can draw a rectangle with these measurements: 6cm and 9cm 5cm and 10cm 7cm and 8cm
To find the perimeter of a shape, you simply add up the lengths of all its sides. In this case, the perimeter would be 8cm + 6cm + 2cm + 5cm + 3cm + 8cm, which equals 32cm. So, the perimeter of the shape with sides measuring 8cm, 6cm, 2cm, 5cm, 3cm, and 8cm is 32cm.
The lengths of the sides does not provide enough information to answer the question.
The largest angle will be opposite length 8cm and by using the cosine rule it works out as 125.1 degrees rounded to one decimal place
105cm2
It is sqrt(62 + 102 + 82) = sqrt(200) = 60.53 cm (approx).
This is not an equilateral triangle.
Dimensions are given out as length by width 14cm by 1cm 13cm by 2cm 12cm by 3cm 11cm by 4cm 10cm by 5cm 9cm by 6cm 8cm by 7cm And the rest is all repeats of the above.