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How many 8cm pieces can you cut from a 2m long piece of string?

It is: 200/8 = 25


What triangle length are 14cm 3cm 8cm?

It is impossible to get a triangle with the side lengths 14cm, 3cm and 8cm 14cm itself is larger than the sum of two other lengths (3cm + 8cm = 11cm).


What is the lengths of the sides of an equilateral triangle with a perimeter of 24 cm?

8cm !


What is the area of a regular hexagon with side lengths of 8 cm?

The area of a regular hexagon with side lengths of 8cm is about 166.3cm2


How do i draw all possible rectangles with a perimeter of 30cm and sides whose lengths are whole numbers?

The answer is, you can draw a rectangle with these measurements: 6cm and 9cm 5cm and 10cm 7cm and 8cm


What is the perimeter for 8cm 6cm 2cm 5cm 3cm 8cm?

To find the perimeter of a shape, you simply add up the lengths of all its sides. In this case, the perimeter would be 8cm + 6cm + 2cm + 5cm + 3cm + 8cm, which equals 32cm. So, the perimeter of the shape with sides measuring 8cm, 6cm, 2cm, 5cm, 3cm, and 8cm is 32cm.


What is the area of a polygon with 12cm 3cm 8cm 5cm 4cm?

The lengths of the sides does not provide enough information to answer the question.


What is the largest angle of a triangle having lengths of 4cm by 8cm by 5cm?

The largest angle will be opposite length 8cm and by using the cosine rule it works out as 125.1 degrees rounded to one decimal place


Find Surface area of a rectangular based pyramid whose side lengths are 8cm and 5cm ans slanting length 5 cm?

105cm2


What is the length of the longest diagonal inside a cuboid of the lengths 6cm 10cm and 8cm?

It is sqrt(62 + 102 + 82) = sqrt(200) = 60.53 cm (approx).


An equilateral triangle with sides measuring 8cm 9cm and 10 cm?

This is not an equilateral triangle.


What are all the possible rectangles with a perimeter of 30cm and sides whose lengths are whole numbers?

Dimensions are given out as length by width 14cm by 1cm 13cm by 2cm 12cm by 3cm 11cm by 4cm 10cm by 5cm 9cm by 6cm 8cm by 7cm And the rest is all repeats of the above.