five
The word "party" consists of 5 unique letters. The number of ways to arrange these letters is calculated using the factorial of the number of letters, which is 5!. Therefore, the total number of arrangements is 5! = 120.
Forty
The number of different ways you can arrange the letters MNOPQ is the number of permutations of 5 things taken 5 at a time. This is 5 factorial, or 120.
There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.
FOURFour, or Cinco (5) in Spanish.
first -- 5 letters second -- 6 letters third -- 5 letters fourth -- 6 letters fifth -- 5 letters sixth -- 5 letters seventh -- 7 letters eighth -- 6 letters So the nest number would be 5, because there are 5 letters in ninth.
Forty
Five.
The number of different ways you can arrange the letters MNOPQ is the number of permutations of 5 things taken 5 at a time. This is 5 factorial, or 120.
The answer is number 5 F, I, V, E= 4 letters But, still has 5 when the 3 letters-"F", "I", "E" are removed because "V" stands for "5" as in the Roman numbers.
three
Yes, glove has 5 letters.
3
Since in the word "party" no letters are repeated, the letters can be arranged in 5! ways, or 120.
The number of different ways the letters of a word can be arranged, when all the letters are different, is the same as the number of permutations of those letters. In this case, the answer is 5!, or 120.
Today
5-five