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It depends on what you are calling "standard form". 2x = 7 can be solved, but it is a standard form of an algebraic equation.
To express the equation ( y - 2x = 1 ) in standard form, we rearrange it to the form ( Ax + By = C ). Adding ( 2x ) to both sides gives ( 2x + y = 1 ). In standard form, the equation can be written as ( 2x + y - 1 = 0 ).
y=2x y-2x=0 or 2x-y=0
2x+y=1
The standard form of slope intercept equation of a straight line is y = mx + c, where m is the slope and c is the y intercept (when x = 0) y = 2x - 4 ...has a slope of 2 y = 2x + 3...also has a slope of 2 So, the two lines are PARALLEL
It depends on what you are calling "standard form". 2x = 7 can be solved, but it is a standard form of an algebraic equation.
To express the equation ( y - 2x = 1 ) in standard form, we rearrange it to the form ( Ax + By = C ). Adding ( 2x ) to both sides gives ( 2x + y = 1 ). In standard form, the equation can be written as ( 2x + y - 1 = 0 ).
1
2X - y - 8 = 0the standard form of the equation is y = mx + chere you have to write the given equation in the standard form as in the form of y = mx + c2X - y - 8 = 0 - y -8 = -2x-y = -2x +8y = 2x -8so the standard form of the given equation is y = 2x - 8
y=2x y-2x=0 or 2x-y=0
2x+3y-5=0
16
2x+y=1
What is the standard form for (2x+7)(x-1)=0
It is: y = 2x-3
The standard form of slope intercept equation of a straight line is y = mx + c, where m is the slope and c is the y intercept (when x = 0) y = 2x - 4 ...has a slope of 2 y = 2x + 3...also has a slope of 2 So, the two lines are PARALLEL
The standard form for the equation of a straight line is ax + by + c = 0