Depending on the value of the slope or gradient if its the same then they are parallel if its a reciprocal then they are perpendicular.
If the slope of the equations are the same then they are parallel If the slope of the equations are minus reciprocal then they are perpendicular If the slope of the equations are different then they are neither
If you mean the perpendicular distance then it is worked out as follows:- Equation: y = 2x+10 Perpendicular slope: -1/2 Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10 The two equations intersect at: (-2,6) Perpendicular distance is the square root of: (-2-2)2+(6-4)2 = 4.472 to 3 d.p.
Any one of them that has a slope of 9/2 or 4.5
When they meet at right angles when plotted on the coordinated grid.
If 2 equations are perpendicular to one another they can have different y-intercepts, depending on how they are situated on a (x,y) graph.
Depending on the value of the slope or gradient if its the same then they are parallel if its a reciprocal then they are perpendicular.
If the slope of the equations are the same then they are parallel If the slope of the equations are minus reciprocal then they are perpendicular If the slope of the equations are different then they are neither
of mutually perpendicular lines.
Base on the slope of two linear equations (form: y = mx+b, where slope is m): - If slopes are equal, the 2 graphs are parallel - If the product of two slopes equals to -1, the 2 graphs are perpendicular. If none of the above, then the 2 graphs are neither parallel nor perpendicular.
If you mean the perpendicular distance then it is worked out as follows:- Equation: y = 2x+10 Perpendicular slope: -1/2 Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10 The two equations intersect at: (-2,6) Perpendicular distance is the square root of: (-2-2)2+(6-4)2 = 4.472 to 3 d.p.
Any one of them that has a slope of 9/2 or 4.5
No, two lines perpendicular to each other are wriiten as two separate equations. Both are linear.
It is perpendicular to a family of other linear equations: of the form 4y = x + c
perpendicular
Endpoints of diameter: (10, -4) and (2, 2)Midpoint which is the center of the circle: (6, -1)Distance from (10, -4) or (2, 2) to (6, -1) = 5 which is the radius of the circleEquation of the circle: (x-6)^2 +(y+1)^2 = 25Slope of radius: -3/4Slope of perpendicular equations which will be parallel: 4/31st perpendicular equation: y--4 = 4/3(x-10) => 3y = 4x-522nd perpendicular equation: y-2 = 4/3(x-2) => 3y = 4x-2
Points: (4, -2) Equation: 2x-y-5 = 0 Perpendicular equation: x+2y = 0 Equations intersect at: (2, -1) Perpendicular distance is the square root of: (2-4)2+(-1--2)2 = 5 Distance = square root of 5