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3+3=6 - Math Wiz
It is used to represent factorial. For example, n! is equal to n(n-1)(n-2)(n-3)...(1).
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Ok, SO if 4 students can do 80 math problems in one hour, each student can do 20 math problems an hour. This is because 80 math problems divided by 4 students/kids is 20, well 80 divided by or / by 4 is twenty. Ok, so each student can do twenty problems an hour, and twenty multiplied by 8 (because there are now eight students doing math problems) is 160. So, that is in one hour. So, then, to, find, how much they can do in 3 hours, multiply this by 3 because 160/h multiplied by 3 is x/3r. so now 160x3 is 480, so 8 students can do 480 math problems in 3 hours.Hope this helps!
-9;-1;4;-4 =24 how all that calculate equal 24 why?
There are infinitely many math problems whose solution would be -7. Here is a simple algebra problem: x + 10 = 3. What is x? The answer (you guessed it) is -7.
An infinite number of possibilities. 1 - 3 = or 1.1 - 3.1 = are two examples.
6 x 3 36/2 10 + 8 24 - 6
It is simple, 15= 5 times 3 so you can write 5 problems in each 3 rows or 3 problems in each 5 rows. Hope I answered your math question correctly!
A comparison in math terms is when you see if two problems are equal to each other.
Oh, dude, there are tons of math problems that equal 17! Like, you could do 8 + 9, or 20 - 3, or even 34 divided by 2. It's like a whole world of possibilities out there in the land of math where 17 reigns supreme.
3+3=6 - Math Wiz
It is used to represent factorial. For example, n! is equal to n(n-1)(n-2)(n-3)...(1).
Well, honey, the problems that equal 6 are as follows: 3+3, 1+5, 2x3, and 12 divided by 2. So, there you have it, darlin', those are the problems that will give you a grand total of 6. Hope that clears things up for ya!
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Math Problems - 2010 Ophira Eisenberg 1-3 was released on: USA: 5 April 2010
Ok, SO if 4 students can do 80 math problems in one hour, each student can do 20 math problems an hour. This is because 80 math problems divided by 4 students/kids is 20, well 80 divided by or / by 4 is twenty. Ok, so each student can do twenty problems an hour, and twenty multiplied by 8 (because there are now eight students doing math problems) is 160. So, that is in one hour. So, then, to, find, how much they can do in 3 hours, multiply this by 3 because 160/h multiplied by 3 is x/3r. so now 160x3 is 480, so 8 students can do 480 math problems in 3 hours.Hope this helps!