Q: What methods could you use to calculate the x-coordinate of the midpoint of a horizontal segment with the end points of negative 20 0 and 20 0?

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It is: (1, -1.5)

Yes. Angles may be measured from the direction of the positive horizontal axis and, clockwise is negative, anticlockwise is positive.

Y-axis is a vertical axis consisting of positive values and negative values.It is perpendicular to x-axis(which is horizontal axis).

The equation is [ y = 3 ].

To find the mid point, find the mean average of each of the x and y coordinates: mid point is at ((3 + -6) ÷ 2, (5 + -6) ÷ 2) = (-1.5, -0.5)

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It is: (1, -1.5)

For triangle ABC, find the midpoint of side BC. Then, find the slope of side BC and use its negative reciprocal (since the negative reciprocal slope is the slope of the right bisector joining side BC and the opposite vertex). Finally, substitute the midpoint and negative reciprocal slope into the y=mx+b equation to get "b", then write the equation. :)

The LCM is defined as being a positive integer. Ignore the negative signs. Calculate as if everything's positive.

Yes. Angles may be measured from the direction of the positive horizontal axis and, clockwise is negative, anticlockwise is positive.

The term negative superelevation is when the driving surface of a vehicle or device has sloped or has become askew from its center or its horizontal curve.

Y-axis is a vertical axis consisting of positive values and negative values.It is perpendicular to x-axis(which is horizontal axis).

It is a horizontal line that intersects the y axis at negative 1

It is part of the negative and positive horizontal x axis on the Cartesian plane

When the horizontal variable goes from positive to negative.

The equation is [ y = 3 ].

You calculate the value of the discriminant. If the answer is less that zero, that is, if the answer has a minus sign in front then it is negative.

To find the mid point, find the mean average of each of the x and y coordinates: mid point is at ((3 + -6) ÷ 2, (5 + -6) ÷ 2) = (-1.5, -0.5)