There are 98 numbers are between 1 and 100 that are divisible by five.
There are 66 numbers between 1 and 100 that are divisible by two or three.
100
100 ÷ 4 = 25 → 24 numbers between 0 and 100 exclusive are divisible by 4 100 ÷ 6 = 16 2/3 → 16 numbers between 0 and 100 are divisible by 6 lcm(4, 6) = 12 → 100 ÷ 12 = 8 1/3 → 8 numbers between 0 and 100 are divisible by 4 and 6.
4 x 25 = 100, so 100 is the 25th number divisible by 4.If you include 100, there are 25.If you don't include 100, there are 24.
101
There are 98 numbers are between 1 and 100 that are divisible by five.
87 is divisible by 1, 3, 29, and 87. 100 is divisible by 1, 2, 4, 5, 10, 20, 25, 50, and 100, therefore the only number divisible by 87 and 100 is 1.
There are 49 numbers between 1 and 100 that are divisible by two.
There are 27 numbers between 1 and 100 that are divisible by three but not by five.
There are 66 numbers between 1 and 100 that are divisible by two or three.
33 numbers between 1 and 100 are divisible by 3.
-1
There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.
The first whole number divisible by 3 is 102 and the last one 399. Let n be the number of whole numbers between 102 and 399 102 + (n - 1)x3 = 399 (this is an arithmetic progression) Solving n, n-1 = (399 - 102)/3 = 99 n = 100 Since even whole numbers among these 100 will be divisible by 6, the number not divisible is half of 100, i.e. 50. regards, lpokbeng
There are 14 numbers between 1 & 100 that are divisible by 7.
101