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How many whole number between 100 and 400 are divisible by 3 but not divisible by 6?
The first whole number divisible by 3 is 102 and the last one 399.
Let n be the number of whole numbers between 102 and 399
102 + (n - 1)x3 = 399 (this is an arithmetic progression)
Solving n, n-1 = (399 - 102)/3 = 99
n = 100
Since even whole numbers among these 100 will be divisible by 6, the number not divisible is half of 100, i.e. 50.
regards,
lpokbeng
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