The first whole number divisible by 3 is 102 and the last one 399.
Let n be the number of whole numbers between 102 and 399
102 + (n - 1)x3 = 399 (this is an arithmetic progression)
Solving n, n-1 = (399 - 102)/3 = 99
n = 100
Since even whole numbers among these 100 will be divisible by 6, the number not divisible is half of 100, i.e. 50.
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lpokbeng
dont kno so just helpp friendds!
There are many numbers between 500 and 1000 divisible by 3 and 9. Any number divisible by 9 is divisible by 3. How about 900?
33 numbers between 1 and 100 are divisible by 3.
251
7 is only divisible by itself and one because it is a prime number.
dont kno so just helpp friendds!
An infinite number.
There are many numbers between 500 and 1000 divisible by 3 and 9. Any number divisible by 9 is divisible by 3. How about 900?
There are 5 multiples of 18 between 200 and 300. (An even number divisible by 9 is any number divisible by 18).
48 is divisible by ten factors. There is an infinite amount of numbers divisible by 48.
33 numbers between 1 and 100 are divisible by 3.
Two of them.
There are 33 such numbers.
251
18 numbers are there
There are infinitely many numbers divisible by 63, just multiply 63 by any whole number and you'll get one.
Here is a list of whole numbers less than 100 which are evenly divisible by 7714212835424956637077849198