16 \;p
29
59
57
58
16 \;p
29
59
3
57
58
5
301 is one such number.
solve it with a calculater
24
6
7, 37, 67, 97, 127, and an infinite number of other numbers in this series (starting with 7 and increasing in increments of 30) have a remainder of 1 when divided by 6 and a remainder of 2 when divided by 5.