To find a number that 2345 and 6 both leave a remainder of 1 when divided, we can subtract 1 from both numbers. So, we calculate 2345 - 1 = 2344 and 6 - 1 = 5. The number we are looking for is the least common multiple (LCM) of 2344 and 5, which is 2344 itself. Therefore, the number is 2344.
301
To find a number that, when divided by either 2345 or 6, has a remainder of 1, we can express this mathematically. The number can be represented as ( n = 2345k + 1 ) for some integer ( k ) when considering division by 2345, and similarly as ( n = 6m + 1 ) for some integer ( m ) when considering division by 6. Therefore, any number of the form ( n = 2345k + 1 ) will have a remainder of 1 when divided by 2345, and we can find values of ( k ) that also satisfy ( n \equiv 1 \mod 6 ). For example, ( n = 1 ) fits both conditions.
A 2 digit number divided by a four digit number, such as 2345, will leave the whole 2-digit number as a remainder. It cannot leave a remainder of 1.
A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.
solve it with a calculater
301
To find a number that, when divided by either 2345 or 6, has a remainder of 1, we can express this mathematically. The number can be represented as ( n = 2345k + 1 ) for some integer ( k ) when considering division by 2345, and similarly as ( n = 6m + 1 ) for some integer ( m ) when considering division by 6. Therefore, any number of the form ( n = 2345k + 1 ) will have a remainder of 1 when divided by 2345, and we can find values of ( k ) that also satisfy ( n \equiv 1 \mod 6 ). For example, ( n = 1 ) fits both conditions.
A 2 digit number divided by a four digit number, such as 2345, will leave the whole 2-digit number as a remainder. It cannot leave a remainder of 1.
A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.
solve it with a calculater
3 divided by 2 has a remainder of 1. Which is 1 less than 2.
57
58
59
29
It is an integer which, when divided by 2, leaves a remainder of 1.
85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11