The best way to find the least common multiple of 3 numbers is to find it of the biggest two, then find the LCM of that answer with the third number.
LCM(a,b) = (ab)/GCF(a,b)
12 factors to [2 2 3]
8 factors to [2 2 2]
common factors are [2 2] = 4
12 * 8 / 4 = 24
Since 5 is prime and not a factor of 24, the GCF(5,24)=1 ("relatively prime")
LCM = 24 * 5 / 1 = 120■
2 8/2 = 4 10/2 = 5 12/2 = 6
12 with 5 remaining 101 - 5 = 96 = 8 x 12
101/8 = 12 and 5/12.
101 ÷ 8 = 12 with remainder 5 or 12.625 times.12, remainder 5
8 x 12 = 96 106 - 96 = 10 10/12 = 5/6 therefore 8 5/6
2 8/2 = 4 10/2 = 5 12/2 = 6
12 with 5 remaining 101 - 5 = 96 = 8 x 12
101/8 = 12 and 5/12.
Their LCM is 280
5, remainder 8
101 ÷ 8 = 12 with remainder 5 or 12.625 times.12, remainder 5
yes
17
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5 can only go into numbers ending 5 or 0 12 can only go into numbers ending in even numbers 2 4 6 8 or 0 So 12 cannot go into numbers ending in 5 So 5 and 12 can only go into numbers ending 0 that are also multiples of 12 Answer: 60 120 180 240 300 360 420 and so on ...
they all go into 120
{5, 5, 8, 8, 12}{5, 5, 8, 8, 12}{5, 5, 8, 8, 12}{5, 5, 8, 8, 12}