6044
1339
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
To write a six-digit number with the 5 in the ten thousands place and the 2 in the ones place, you can start by placing the 5 in the second digit from the left (the ten thousands place). Then, place the 2 in the far right position (the ones place). You can fill the remaining digits (hundreds of thousands, thousands, and hundreds) with any digits, including zeros, to complete the number. For example, a possible number could be 500,042.
this question doesnt make sense
The standard form of 27 thousands, 3 hundreds, and 5 ones is 27,305. In standard form, we write the number using commas to separate groups of three digits, starting from the right. In this case, we have 27 thousands, 3 hundreds, and 5 ones, which combine to form the number 27,305.
1339
In the number 4200, there are no ones. The digits represent 4 thousands, 2 hundreds, 0 tens, and 0 ones. Therefore, the count of ones is 0.
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
To write a six-digit number with the 5 in the ten thousands place and the 2 in the ones place, you can start by placing the 5 in the second digit from the left (the ten thousands place). Then, place the 2 in the far right position (the ones place). You can fill the remaining digits (hundreds of thousands, thousands, and hundreds) with any digits, including zeros, to complete the number. For example, a possible number could be 500,042.
this question doesnt make sense
The standard form of 27 thousands, 3 hundreds, and 5 ones is 27,305. In standard form, we write the number using commas to separate groups of three digits, starting from the right. In this case, we have 27 thousands, 3 hundreds, and 5 ones, which combine to form the number 27,305.
2230
There is a lot of answer for this, but I tell you one. The answer is 6541.
The digit in the hundreds place of the number 1098 is 0. In the number 1098, the digits are arranged as follows: 1 in the thousands place, 0 in the hundreds place, 9 in the tens place, and 8 in the ones place.
38977 is in ones place9 is in tens place (and is three times the number in thousands place)8 is in the hundreds place3 is in the thousands place7+9+8+3=27
412
The number is 1193.