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Q: What number is a multiple of 10 greater than 100 but less than 200 and even?

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No, as a multiple has to be greater than or equal the original number, and 118 is less than 271.

The number is 54. It is greater than 36 and less than 70. One of its factors is 9 and it is an even number.

The three digit number satisfying the requirements is 112. The three digit number must be greater than or equal to 100 and less than 140. To have 7 as a factor it must be a multiple of 7 To be even, it must be an even multiple of 7. The first even multiple of 7 greater than or equal to 100 is: 100 ÷ 7 = 14 r 2 → first even multiple is 16 × 7 = 112 The last even multiples of 7 less than 140 is: 140 ÷ 7 = 20 → last even multiple is 18 × 7 = 126 The sum of its digits must be less than 9: 112 → 1 + 1 + 2 = 4 126 → 1 + 2 + 6 = 9 → only 112 fits all the criteria.

No, however there are even numbers less than 15. An even number is any number that can be divided by two evenly, so it can be greater than 15 too.

510

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14

No, as a multiple has to be greater than or equal the original number, and 118 is less than 271.

Given any number, there is an even number that exists greater than it. That even number is a product: of 2 and some number. Therefore, the number that you started with is less than the product of a pair of numbers.

27

The number is 54. It is greater than 36 and less than 70. One of its factors is 9 and it is an even number.

The three digit number satisfying the requirements is 112. The three digit number must be greater than or equal to 100 and less than 140. To have 7 as a factor it must be a multiple of 7 To be even, it must be an even multiple of 7. The first even multiple of 7 greater than or equal to 100 is: 100 ÷ 7 = 14 r 2 → first even multiple is 16 × 7 = 112 The last even multiples of 7 less than 140 is: 140 ÷ 7 = 20 → last even multiple is 18 × 7 = 126 The sum of its digits must be less than 9: 112 → 1 + 1 + 2 = 4 126 → 1 + 2 + 6 = 9 → only 112 fits all the criteria.

989. If there is a remainder of 2 when divided by 3, the number is one less than a multiple of 3. If there is a remainder of 4 when divided by 5, the number is one less than a multiple of 5. Thus the number required is one less than a multiple of the lowest common multiple of 3 and 5 (that is 15). So what is needed is an even multiple of 15 less than or equal to 1000: 1000 ÷ 15 = 662/3 Thus the highest even multiple of 15 not greater than 1000 is 66 x 15 = 990, and the required number is 989.

NONE.The number that is greater than 11 but less than 13 is 12 and 12 is an even number.

150

There is no such number. For if you considered 49.99 to be such a number, then 49.995 is a greater number and it is less than 50. And then 49.9955 is even greater and still less than 50. This process can go on without end.

Every second number greater than 2 is an even number.