36*36 = 1296 and 37*37 = 1369
So sqrt(1300) lies between -37 and -36 or 36 and 37
So, the number before the square root of 1300 is either -37 or +36
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The square root of -1300 is an imaginary number which is expressed as a multiple of i where i = -11/2 (i.e. i equals the square root of -1).So,-13001/2 = 13001/2 * -11/2 = 36.06 (to two decimal places) * -11/2 = 36.06i (to two decimal places)
The number of digits in the square root of a number depends on the number. If it is a square number, the square root will have a finite number of digits. If the number is not a square number then the square root will be an irrational number with an infinite, non-repeating decimal representation. In both cases, the number of digits before the decimal point, in the square root of x will be the rounded value of 1+0.5*log10(x)
The square of number is a *a ( a number times itself ). For example, 4*4=16, so the square of 4 is 16. the square root is the number before you square it. The square root of 16 is 4. It actually simple to remember this way: think of the root as the root of a tree, growing to multiply itself.