Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.
41 is a prime number, and is divisible by nothing except 1 and itself.
740 is divisible by both 4 and 5.
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
15 is the smallest number divisible by both 3 and 5
Because 10 is divisible by both 2 and 5
A number divisible by both 2 and 5 will be divisible by their product (2 x 5), which is 10. Any number divisible by 10 ends in 0. The only number listed that ends in 0 is 110.
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
No
10
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
No. The smallest number divisible by both 5 and 2 is their lowest common Multiple (LCM) which is 10; ALL multiples of their LCM are divisible by 5 and 2, ie 10, 20, 30, 40, 50, ... are all divisible by 5 and 2.
Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.
99,996
41 is a prime number, and is divisible by nothing except 1 and itself.
An "even" number is a number that is divisible by 2. Since 5 is not divisible by 2, it is an "odd" number.
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.