17 tens is equal to 170 (since 1 ten is equal to 10). Adding 6 ones to 170 gives us a total of 176. So, the number represented by 17 tens and 6 ones is 176.
To convert ones to tens, you need to divide by 10. In this case, 90 ones divided by 10 equals 9 tens. Each ten is equivalent to 10 ones, so 90 ones is equal to 9 tens.
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
The number with 6 tens and 11 ones can be calculated by multiplying the number of tens by 10 and adding the number of ones. Therefore, 6 tens is 60 (6 x 10) and 11 ones is 11. Adding these together, 60 + 11 equals 71. Thus, the number is 71.
The general function is:1. y = a*x+bb is irrelevant and we can be removed2. y = a*xlets split x into ones and tens3. x = tens*10 + ones /e.g. 23 = 2*10 + 34. p1 = Multiplier of the onesp2 = Multiplier of the tens5. y = tens*10*p2 + ones*p1 /according to the question6. x*a = tens*10*p2 + ones*p1 /according to 2.7. (tens*10 + ones)*a = tens*10*p2 + ones*p1 /according to 3.8. tens*10*a + ones*a = tens*10*p2 + ones*p1 /regroup9. tens*10*a - tens*10*p2 + ones*a - ones*p1 = 0 /regroup10. tens*10*(a-p2) + ones*(a-p1) = 0 /regroup11. assuming "tens" and "ones" are not 0 then (a-p2) and (a-p1) must be 012. a-p2 = 0a-p1 = 013. a = p2a = p114. a = p1 = p2the answer is: when the Multipliers of ones and tens are equal then the product is called a.
The number that has 3 tens and 2 ones is 32. In the base-10 number system, each place value represents a power of 10, so the digit in the tens place is multiplied by 10 and the digit in the ones place remains as it is. Therefore, 3 tens is equal to 30 and 2 ones is equal to 2, making the number 32.
17 tens is equal to 170 (since 1 ten is equal to 10). Adding 6 ones to 170 gives us a total of 176. So, the number represented by 17 tens and 6 ones is 176.
To convert ones to tens, you need to divide by 10. In this case, 90 ones divided by 10 equals 9 tens. Each ten is equivalent to 10 ones, so 90 ones is equal to 9 tens.
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
The number with 6 tens and 11 ones can be calculated by multiplying the number of tens by 10 and adding the number of ones. Therefore, 6 tens is 60 (6 x 10) and 11 ones is 11. Adding these together, 60 + 11 equals 71. Thus, the number is 71.
16
The general function is:1. y = a*x+bb is irrelevant and we can be removed2. y = a*xlets split x into ones and tens3. x = tens*10 + ones /e.g. 23 = 2*10 + 34. p1 = Multiplier of the onesp2 = Multiplier of the tens5. y = tens*10*p2 + ones*p1 /according to the question6. x*a = tens*10*p2 + ones*p1 /according to 2.7. (tens*10 + ones)*a = tens*10*p2 + ones*p1 /according to 3.8. tens*10*a + ones*a = tens*10*p2 + ones*p1 /regroup9. tens*10*a - tens*10*p2 + ones*a - ones*p1 = 0 /regroup10. tens*10*(a-p2) + ones*(a-p1) = 0 /regroup11. assuming "tens" and "ones" are not 0 then (a-p2) and (a-p1) must be 012. a-p2 = 0a-p1 = 013. a = p2a = p114. a = p1 = p2the answer is: when the Multipliers of ones and tens are equal then the product is called a.
To find the number represented by 7 tens and 9 ones, you would multiply 7 by 10 (since there are 10 ones in a ten) to get 70, and then add the 9 ones to get the final number. Therefore, 7 tens and 9 ones is equal to 79.
One hundred.
To convert hundreds to tens, you multiply the number of hundreds by 10. Therefore, 300 hundreds is equal to 300 × 10, which equals 3,000 tens.
Nine tens = 90 Ten ones = 10 90 + 10 = 100
100 = (9x10) + (10x1) = 90 + 10