There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
The general function is:1. y = a*x+bb is irrelevant and we can be removed2. y = a*xlets split x into ones and tens3. x = tens*10 + ones /e.g. 23 = 2*10 + 34. p1 = Multiplier of the onesp2 = Multiplier of the tens5. y = tens*10*p2 + ones*p1 /according to the question6. x*a = tens*10*p2 + ones*p1 /according to 2.7. (tens*10 + ones)*a = tens*10*p2 + ones*p1 /according to 3.8. tens*10*a + ones*a = tens*10*p2 + ones*p1 /regroup9. tens*10*a - tens*10*p2 + ones*a - ones*p1 = 0 /regroup10. tens*10*(a-p2) + ones*(a-p1) = 0 /regroup11. assuming "tens" and "ones" are not 0 then (a-p2) and (a-p1) must be 012. a-p2 = 0a-p1 = 013. a = p2a = p114. a = p1 = p2the answer is: when the Multipliers of ones and tens are equal then the product is called a.
100 = (9x10) + (10x1) = 90 + 10
To determine how many tens equal 10,000, you need to divide 10,000 by 10. This division results in 1,000, meaning there are 1,000 tens in 10,000. Each ten represents a factor of 10 in the number, so dividing the total by 10 gives you the number of tens.
Well, isn't that a happy little question! If we have 80 ones, we can group them into sets of ten. So, there are 8 groups of ten in 80 ones. Just imagine those tens dancing together on your canvas, creating a beautiful harmony of numbers.
The number that has 3 tens and 2 ones is 32. In the base-10 number system, each place value represents a power of 10, so the digit in the tens place is multiplied by 10 and the digit in the ones place remains as it is. Therefore, 3 tens is equal to 30 and 2 ones is equal to 2, making the number 32.
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
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The general function is:1. y = a*x+bb is irrelevant and we can be removed2. y = a*xlets split x into ones and tens3. x = tens*10 + ones /e.g. 23 = 2*10 + 34. p1 = Multiplier of the onesp2 = Multiplier of the tens5. y = tens*10*p2 + ones*p1 /according to the question6. x*a = tens*10*p2 + ones*p1 /according to 2.7. (tens*10 + ones)*a = tens*10*p2 + ones*p1 /according to 3.8. tens*10*a + ones*a = tens*10*p2 + ones*p1 /regroup9. tens*10*a - tens*10*p2 + ones*a - ones*p1 = 0 /regroup10. tens*10*(a-p2) + ones*(a-p1) = 0 /regroup11. assuming "tens" and "ones" are not 0 then (a-p2) and (a-p1) must be 012. a-p2 = 0a-p1 = 013. a = p2a = p114. a = p1 = p2the answer is: when the Multipliers of ones and tens are equal then the product is called a.
To find the number represented by 7 tens and 9 ones, you would multiply 7 by 10 (since there are 10 ones in a ten) to get 70, and then add the 9 ones to get the final number. Therefore, 7 tens and 9 ones is equal to 79.
One hundred.
The number that has 3 tens and 8 ones is 38. In the decimal system, each digit's place value increases by a factor of 10 from right to left. Therefore, the digit in the tens place represents the number of tens (3), and the digit in the ones place represents the number of ones (8).
Nine tens = 90 Ten ones = 10 90 + 10 = 100
100 = (9x10) + (10x1) = 90 + 10
To determine how many tens equal 10,000, you need to divide 10,000 by 10. This division results in 1,000, meaning there are 1,000 tens in 10,000. Each ten represents a factor of 10 in the number, so dividing the total by 10 gives you the number of tens.
No, 100 is not the same as 10 ones or 10 tens. In the decimal system, 100 is equivalent to 10 tens. This is because each place value in a number represents a power of 10. So, in the number 100, the digit '1' is in the hundreds place, indicating 1 hundred which is equivalent to 10 tens.
9 tens + 12 ones = 9 × 10 + 12 × 1 = 90 + 12 = 102.