It is the fact that 13*5 = 65.
Yes - any number ending with a 0 or 5, including 325, is divisible by 5. In this instance, 325/5 = 65
If a number is divisible by 10 (i.e. 100) then it is also divisible by 5. Ex: 100 by 10, is 10 by 5, is 20 20 by 10 is 2 by 5 is 4 The number of times it is divisible by 5 will always be double the number of times it is divisible by 10, which makes sense because 10 is double 5.
It's 65 65 is not prime; it is divisible by 5 and 13. The next prime after 63 is 67.
No. To be divisible by 10, the last digit must be a zero (0); 65 ends with a five (5) and thus is not divisible by 10.
Yes. All numbers ending in 5 or 0 are divisible by 5.65/5 = 13
All multiples of 65, which is an infinite number.
Yes - any number ending with a 0 or 5, including 325, is divisible by 5. In this instance, 325/5 = 65
no, it is divisible by 1, 5, 13, 65
Yes. Any number ending in 0 is divisible by 10, which automatically makes it divisible by 5 as well.
A number divisible by both 2 and 5 will be divisible by their product (2 x 5), which is 10. Any number divisible by 10 ends in 0. The only number listed that ends in 0 is 110.
65 = 13*5, 13 and 5 are prime numbers
If a number is divisible by 10 (i.e. 100) then it is also divisible by 5. Ex: 100 by 10, is 10 by 5, is 20 20 by 10 is 2 by 5 is 4 The number of times it is divisible by 5 will always be double the number of times it is divisible by 10, which makes sense because 10 is double 5.
it is divisible by 5
It's 65 65 is not prime; it is divisible by 5 and 13. The next prime after 63 is 67.
65 is divisible by 1, 5, 13, 65.
65
To find a number between 55 and 65 that is divisible by 2, 3, 4, 5, 6, 10, and 12, we need to find the least common multiple (LCM) of these numbers. The LCM of 2, 3, 4, 5, 6, 10, and 12 is 60. Therefore, the number between 55 and 65 that is divisible by all these numbers is 60.