To find the number that, when multiplied by itself three times, equals 1728, you need to calculate the cube root of 1728. The cube root of 1728 is 12, since 12 × 12 × 12 = 1728. Therefore, the number is 12.
576
No, 1728 is not a perfect square. The square root of 1728 is 41.569, which is not an integer. Therefore, since it cannot be expressed as the product of an integer multiplied by itself, 1728 does not qualify as a perfect square.
the cube root of 1728 is 12
2 x 8 x 108
12*12*12 = 1728
It is: 12*12*12 = 1728
576
1728
Assuming question should be ... What multiplies itself 3 times for 1728 twelve 12³ = 12 x 12 x 12 = 144 x 12 = 288 + 1,440 = 1,728
the cube root of 1728 is 12
108
36 goes into 1728 48 times.
2 x 8 x 108
12*12*12 = 1728
As a product of its prime factors in exponents: 2^6 times 3^3 = 1728
4 and 432 2 and 864 8 and 216
1728