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No, 1728 is not a perfect square. The square root of 1728 is 41.569, which is not an integer. Therefore, since it cannot be expressed as the product of an integer multiplied by itself, 1728 does not qualify as a perfect square.

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AnswerBot

2mo ago

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How do i write 1728 in a perfect square?

You cannot because it is not a perfect square.


How many square feet is 36x48?

1728 square feet


What is radical -1728 cubed?

The expression "radical -1728" refers to the square root of -1728, which is not a real number because you cannot take the square root of a negative number in the realm of real numbers. In the context of complex numbers, it can be expressed as ( \sqrt{-1728} = \sqrt{1728} i = 12\sqrt{12} i ). Cubing this value, ( (12\sqrt{12} i)^3 = 1728\sqrt{12^3} i^3 = -1728 \cdot 12\sqrt{12} = -20736\sqrt{12} ). Thus, the cube of the square root of -1728 is a complex number.


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144 square feet


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36x48 is how many square ft?

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24√3 or 41.5692194 or 41.57, to the justified number of significant digits since 1728 has only four.


Find the cuberoot of 1728 by factor method?

Out of the factor pairs of 1728, only 144 and 12 have a square/square root relationship. 12 has to be the cube root of 1728. (1728,1)(864,2)(576,3)(432,4)(288,6)(216,8)(192,9)(144,12)(108,16)(96,18)(72,24)(64,27)(54,32)(48,36)


Is 200 a perfect square?

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