Let's first call the number x. We can rewrite the clue as an equation: x/3 = 3 + x/4 We can rewrite this as: x/3 - x/4 = 3 Now multiply the whole equation by 12, which is the least common multiple of 3 and 4 4x - 3x = 36
Finally: x = 36
The statement "Four times a number is more than the sum of the number and six" can be expressed mathematically as (4x > x + 6), where (x) represents the number. Simplifying this inequality, we subtract (x) from both sides to get (3x > 6). Dividing by 3, we find that (x > 2). Thus, any number greater than 2 satisfies the condition.
A number that is much more than 15 but less than 29 could be 20, 21, or any number up to 28. For example, 20 is greater than 15 and satisfies the condition of being less than 29. Similarly, 25 would also fit this description.
The number you are looking for has the form ABCDEF, where A, B, C, D, E, and F represent the digits in the number. The condition given can be expressed as A + F = B + E. To find the number greater than one million that satisfies this condition, we can start by examining the possibilities for the digits. One possible number that fits this criterion is 1,234,567.
The number of vertices and faces is 2 more than the number of Edges according to Euler's formula. So a gemstone with 22 edges must have a total of 24 faces and vertices.
To solve the expression, we can represent the unknown number as ( x ). The statement translates to the inequality ( \frac{x}{3} + 6 > 14 ). Simplifying this, we first subtract 6 from both sides to get ( \frac{x}{3} > 8 ). Multiplying both sides by 3 gives us ( x > 24 ). So, any number greater than 24 satisfies the condition.
Every whole number, except 1, satisfies this requirement since it would be the product of 1 and the number itself.
satisfies consumer wants
Suppose the first number is x. Then the second number is x+1. A fourth of the first number is x/4 A fifth of the second number is (x+1)/5 So the equation is x/4 = (x+1)/5 + 1 Multiplying though by 20: 5x = 4x + 4 + 20 = 4x + 24 Subtracting 4x from both sides: x = 24
The statement "Four times a number is more than the sum of the number and six" can be expressed mathematically as (4x > x + 6), where (x) represents the number. Simplifying this inequality, we subtract (x) from both sides to get (3x > 6). Dividing by 3, we find that (x > 2). Thus, any number greater than 2 satisfies the condition.
A number that is much more than 15 but less than 29 could be 20, 21, or any number up to 28. For example, 20 is greater than 15 and satisfies the condition of being less than 29. Similarly, 25 would also fit this description.
The pentagon satisfies those criteria precisely.
Oh honey, that's a big number! That's 300 trillion if you want to get fancy with it. Just a whole lotta zeros stacked up, nothing more, nothing less. Hope that satisfies your curiosity, darling!
28 is the smallest number which satisfies these constraints, the next smallest numbers are 30, 32, and 36. This can be eaily calculated as the divisor function is a series on oeis A000005. 21 hsa 4 factors; 1, 3, 7, 21 as it is semi prime.
one fourth is the same as .25, because .25 or 25cents is one fourth of 100 or a dollar,same as saying a fourth of 100 or a dollar is .25 or25 cents. Hope that helped, if it didn't ask an adult or a teacher, they might be able to help a little bit more
A solution is an answer which satisfies all the constraints posed in the problem. Sometimes there can be more than one solution to a problem, sometimes there are no solutions to a problem. For example the solution to "3x+4=13" is the value of x which satisfies the equation. Of course it's (13-4)/3=3. "Name a day of the week that begins with a T" has two solutions, since Tuesday and Thursday both begin with T. "What number is bigger than 4 but less than 3" has no solutions.
Yes Petersons algo satisfies Mutual exclusion, Progress and bonded waiting and is more efficient than Dekker's algo.
The number you are looking for has the form ABCDEF, where A, B, C, D, E, and F represent the digits in the number. The condition given can be expressed as A + F = B + E. To find the number greater than one million that satisfies this condition, we can start by examining the possibilities for the digits. One possible number that fits this criterion is 1,234,567.