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There exists infinitely many solutions to the problem.

Let the required number be x:

By Euclid's Division Lemma we have

x = 9q + 1(Since dividend is 9 and remainder is 1)

Put any value of q(q must be natural number), say 5.

On putting q = 5, we get x = 9*5 + 1 = 46.

Put any value of q and you will get different value of x.

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Q: What number when you divide by 9 has a reminder 1?
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