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There exists infinitely many solutions to the problem.
Let the required number be x:
By Euclid's Division Lemma we have
x = 9q + 1(Since dividend is 9 and remainder is 1)
Put any value of q(q must be natural number), say 5.
On putting q = 5, we get x = 9*5 + 1 = 46.
Put any value of q and you will get different value of x.
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What number am i when you divide me by 5 the reminder is 4?
5 will go into 9 once with a remainder of 4.
What is -9 equals 9q?
q=-1 You do the opposite operation to get rid of a number next to a variable. In this case, since you are multiplying you divide the other side with that number. So you take 9 and divide -9 by 9. This gets rid of the 9 next to the q, and you are left with -1 = q.
What number is next 15 24 25 5 14 15?
3, looks as if you add 9 to the first number, then add 1, divide by 5, add 9, add 1, divide by 5 to get 3
What is the possible remainder when you divide by 9?
The remainder can be any number between 1 and 8 .
Find the reminder when 3336667778889991 divided by 9?
370740864321110.1
