There are 300.
If n is divisible by both 5 and 6, then it should be divisible by 30 (5 * 6). Considering you are asking for only two-digit numbers, the answer(s) would be 30, 60, and 90. So, three numbers.
None is divisible by all those.
U={whole number greater than 10 but smaller than 30 } X={numbers divisible by 3 } Y Odd numbers
24, 30 and 36.
15 is divisible by 1, 3, 5, 15.
which numbers are divisible 6 42 16 26 30 48
There are 300.
Starting at 12 and ending at 99, there are 30 two-digit numbers divisible by three.
If n is divisible by both 5 and 6, then it should be divisible by 30 (5 * 6). Considering you are asking for only two-digit numbers, the answer(s) would be 30, 60, and 90. So, three numbers.
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.
They are both divisible by two.
None is divisible by all those.
All real numbers are divisible by four. However, no numbers with decimal extensions are evenly divisible by four. The only numbers evenly divisible by four between 30 and 39 are 32 and 36. Otherwise, including decimals, there would be an infinite number of rational numbers between those limits divisible by four, and infinitely more than that if the real numbers are included (numbers that cannot be represented by terminating or repeating continued decimal expansions).
U={whole number greater than 10 but smaller than 30 } X={numbers divisible by 3 } Y Odd numbers
6, 9, 12, 30
24, 30 and 36.