293 is not divisible by 5. Only numbers that end on 0 or 5 are exactly divisible by 5.No, it is not.
Only numbers with 5 or 0 as final digit are divisible by 5.
All multiples of 605 are divisible by 605:605, 1210, 1815, 2420, 3025, ...The numbers that 605 is divisible by, ie the numbers that divide 605 exactly, are its factors which are: 1, 5, 11, 55, 121, 605
All numbers are divisble by 5. Only numbers ending in 0 or 5 are evenly (no remainder) divisible by 5.
No. The only numbers that are divisible by 5 are the numbers that end with 5 or 0. In this case, it ends with 6, so 5 is NOT divisible by 998876. =)
293 is not divisible by 5. Only numbers that end on 0 or 5 are exactly divisible by 5.No, it is not.
1, 2, 4, 5, and 10
Any number that ends with 0 or 5 is exactly divisible by 5 except for zero itself.
Only numbers with 5 or 0 as final digit are divisible by 5.
All multiples of 605 are divisible by 605:605, 1210, 1815, 2420, 3025, ...The numbers that 605 is divisible by, ie the numbers that divide 605 exactly, are its factors which are: 1, 5, 11, 55, 121, 605
The numbers that are divisible by 5 has 5 or 0 at the end.So,this numbers are divisible by 5.5,10,15,25,555,10000,etc.
All numbers that end with 5 are divisible by 5.All numbers that end with 5 are divisible by 5.All numbers that end with 5 are divisible by 5.All numbers that end with 5 are divisible by 5.
The smallest number which is exactly divisible by the numbers 8 9 and 10 is 360.
No, because 1 is not evenly divisible by 5. However, all numbers divisible by 5 are divisible by 1.
All numbers are divisble by 5. Only numbers ending in 0 or 5 are evenly (no remainder) divisible by 5.
No.
Yes, all numbers that are divisible by 5 are also divisible by 10. This is because 10 is a multiple of 5. When we say that a number is divisible by 5, we mean that it can be evenly divided by 5 with no remainder. When we say that a number is divisible by 10, we mean that it can be evenly