1, 2, 4.
1, 2, 4 and 8 will go into both numbers evenly with no remainders
No. 64 is not evenly divisible by six.
64/4 = 16 with no remainder. The answer is yes, it does.
Yes, it goes in 16 times (16x4=64)
These whole numbers go evenly into 64: 1, 2, 4, 8, 16, 32, 64.
Only 1.
Only the number one.
1, 2, 4.
2, 4, and 8 will evenly divide into both.
1, 2, 4 and 8 will go into both numbers evenly with no remainders
All of these numbers divide into 64 evenly: 1, 2, 4, 8, 16, 32, 64.
1, 2, 4, 8, 16, 32, 64, 128, 256.
No. These are the numbers that divide evenly into 64: 1 2 4 8 16 32 and 64.
Not evenly.
The lowest common multiple of 64 and 16 is 128. 16x8=128 64x3=128 Both the numbers go into 128 evenly, and since 128 is the lowest multiple that they BOTH go into, it is the LCM of both numbers.
No. 64 is not evenly divisible by six.