Any of its factors including itself
1, 2, 4.
1, 2, 4 and 8 will go into both numbers evenly with no remainders
No, 3 cannot go into 64 evenly. When you divide 64 by 3, the result is 21 with a remainder of 1. This means that 64 is not a multiple of 3.
No. 64 is not evenly divisible by six.
64/4 = 16 with no remainder. The answer is yes, it does.
These whole numbers go evenly into 64: 1, 2, 4, 8, 16, 32, 64.
Only 1.
1, 2, 4.
Only the number one.
2, 4, and 8 will evenly divide into both.
1, 2, 4 and 8 will go into both numbers evenly with no remainders
1, 2, 4, 8, 16, 32, 64, 128, 256.
No. These are the numbers that divide evenly into 64: 1 2 4 8 16 32 and 64.
Not evenly.
The lowest common multiple of 64 and 16 is 128. 16x8=128 64x3=128 Both the numbers go into 128 evenly, and since 128 is the lowest multiple that they BOTH go into, it is the LCM of both numbers.
No. 64 is not evenly divisible by six.
There is no number that can fit evenly into both numbers.