The simplest answer is 1 and 28.
There are an infinite number of pairs that can be multiplied together to make 28, and an infinite number of triplets, quads, etc.
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12 and 28
1 x 28, 2 x 14, 4 x 7 = 28
To find numbers with distinct digits whose product is 28, we first determine the factorization of 28, which is (2^2 \times 7). The distinct digits that can be used are 1, 2, 4, 7, and 8, since they can be combined to form products equal to 28. The valid combinations of these digits are 4, 7, and 1 (as (4 \times 7 \times 1 = 28)), and 2, 4, and 7 (as (2 \times 4 \times 7 = 28)). Therefore, the valid numbers are 147, 174, 417, 471, 714, and 741 from the first combination, and 247, 274, 427, 472, 724, and 742 from the second combination, leading to a total of 12 distinct numbers.
the numbers that can go into 28 are 1,2,4,7,14 and 28.
How many numbers are in 28