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How many numbers with distinct digits are possible the product of whose digits is 28?
To find numbers with distinct digits whose product is 28, we first determine the factorization of 28, which is (2^2 \times 7). The distinct digits that can be used are 1, 2, 4, 7, and 8, since they can be combined to form products equal to 28. The valid combinations of these digits are 4, 7, and 1 (as (4 \times 7 \times 1 = 28)), and 2, 4, and 7 (as (2 \times 4 \times 7 = 28)). Therefore, the valid numbers are 147, 174, 417, 471, 714, and 741 from the first combination, and 247, 274, 427, 472, 724, and 742 from the second combination, leading to a total of 12 distinct numbers.
What else can I help you with?
How many two digits numbers are there in which the product of the digits is even?
two
What are 8 digit odd numbers with all digits different?
There are only five distinct odd digits.
What is a 4 digit ODD numbers have all 4 digits distinct?
5555
Find 5 four digit numbers such that the product of the digits of each four digit prime number are also prime?
You had me until "product." The product of 4 digits can't be prime.
Write a multiplication sentence with the greatest possible product using the digits 1 2 6 and 8 once and then write the sentence with the least possible product?
Using the digits, we can make 81 x 62 equals 5022, which is the largest possible product. To make the smallest possible product, do 268 x 1 = 268.
How many digits can the product of 2-digit numbers have?
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
How many digits can be the product of two digit numbers have to give examples to support your answer?
It can have 4 digits, because the highest possible two digit numbers 99*99=9801.
How many two digits numbers are there in which the product of the digits is even?
two
What is the largest possible product of three 3 digit numbers all of whose digits are different?
Forming three three digit numbers that use the numbers 1-9 without repeating, the highest product possible is 611,721,516. This is formed from the numbers 941, 852, and 763.
What are 8 digit odd numbers with all digits different?
There are only five distinct odd digits.
What is a 4 digit ODD numbers have all 4 digits distinct?
5555
Of example How many digits can the product of two 2 digit numbers have?
It should be obvious (it is, isn't it? am I expecting too much of today's educational system?) that the largest possible result of multiplying two two digit numbers is 99x99 = 9801, which has four digits, and the smallest possible result is 10x10 = 100, which has three digits.
How many 4 digit numbers can are there with distinct digits?
4,536 whole numbers or mixed numbers. 5,040 pure decimals.
How many counting numbers have four distinct nonzero digits such that the sum of the four digits is 10?
1,2,3,4 1+2+3+4=10 4 times 3 times 2 times 1 =24 24 counting numbers
If the three digits numbers x and y are each composed of three distinct non zero digits what is the greatest possible value of x-y?
x is 987 subtract y is 123 ,which 987-123=864.
What even number has digits whose product is ten?
52 is a number whose digits have a product of 10.
How many 5 digit numbers are there with distinct digits?
There are 30,240 different 5-digit numbers. Math: 10*9*8*7*6 1st digit has 10 possible choices (0-9) 2nd digit has 9 possible choices (one of the digits was used in the 1st digit) 3rd digit has 8 possible choices 4th digit has 7 possible choices 5th digit has 6 possible choices
