100 ÷ 4 = 25 → 24 numbers between 0 and 100 exclusive are divisible by 4 100 ÷ 6 = 16 2/3 → 16 numbers between 0 and 100 are divisible by 6 lcm(4, 6) = 12 → 100 ÷ 12 = 8 1/3 → 8 numbers between 0 and 100 are divisible by 4 and 6.
8
There are 12 numbers between 100 and 199 that are divisible by eight: 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184 and 192.
There are a total of 33 numbers - starting with 12, and ending with 99.
There are 8 of them and they are all multiples of 12
100 ÷ 4 = 25 → 24 numbers between 0 and 100 exclusive are divisible by 4 100 ÷ 6 = 16 2/3 → 16 numbers between 0 and 100 are divisible by 6 lcm(4, 6) = 12 → 100 ÷ 12 = 8 1/3 → 8 numbers between 0 and 100 are divisible by 4 and 6.
8
12. 13, if you count 200
A number that is divisible by 4 and 6 must be divisible by the LCM of 4 and 6 which is 12. 100/12 = 8.33 200/12 = 16.67 So, there are 16 numbers below 200 that are divisible by 4 and 6 and, of these, 8 are smaller than 100. That gives 16 - 8 = 8 between 100 and 200.
There are 12 numbers between 100 and 199 that are divisible by eight: 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184 and 192.
There are a total of 33 numbers - starting with 12, and ending with 99.
There are 75 multiples of 12 between 100 and 1000.
They are all the multiples of 12 and there are 8 of them
Oh, dude, let me break it down for you. So, to find the numbers divisible by both 3 and 4, you need to find the numbers divisible by their least common multiple, which is 12. From 100 to 999, every 12th number is divisible by 12. So, you just need to find how many multiples of 12 are there between 100 and 999. It's like a piece of cake, you got this!
There are 8 of them and they are all multiples of 12
To be divisible by both 4 and 5, the number has to be divisible by 20. Therefore, there are 12 numbers between 1 and 240, inclusive, which are divisible by 4 and 5: 20, 40, 60, 80, 100, 120, 140, 160, 180, 200, 220, 240.
4, 8, 12, 16, 20 and just keep adding 4 until you get to 100.