There are 8 of them and they are all multiples of 12
There are 50 of them.
Exactly 50
Twenty of them.
Divisible by both? 2 numbers... 45 and 90
From 10 to 99 (inclusive) there are 90 numbers.18 are evenly divisible by 5.Therefore 72 are not.
To be divisible by both 4 and 5, the number has to be divisible by 20. Therefore, there are 12 numbers between 1 and 240, inclusive, which are divisible by 4 and 5: 20, 40, 60, 80, 100, 120, 140, 160, 180, 200, 220, 240.
There are 39 natural numbers between 1,000 and 1,500, inclusive, that are divisible by 13.
between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.
Seven of them.
34 of them.
Exactly 50
Twenty of them.
343!
They are all the multiples of 12 and there are 8 of them
193 of them are divisible by one (or more) of the given numbers.
From 1 (inclusive) to 1000(inclusive,) 750.
There are 1,000 positive integers between 1,000 and 9,999, inclusive, that are divisible by nine.
There are no numbers that are divisible by 21 but not by 7 so the "or 21" part of the question can be ignored.There are 166 numbers between 1 and 1000 that are divisible by 6. However, 23 of those are also divisible by 7.So 166 - 23 = 143 numbers.