39*3=117 39*5=195
Their LCM is 117
5x39=195
1, 3, 9, 13, 39, 117
1, 3, 9, 13, 39, 117
They are: 1 and 9
9 and 13 both go into 117.
3 and 9
An infinite number. 117, 234, 351, 468, 585, 702, 819, 936, 1053 +117 . . .
these are all the real numbers that go into 370 1*370 2*195 5*74 10*37 37*10 74*5 195*2 370*1
1, 3, 9, 13, 27, 39, 117, 351.
1. Start the problem using algebra and set up an equation. (you could use guess and check but that would take longer, especially for more difficult problems) 2. If the problem states consecutive numbers and gives no other information, we can assume they are numbers that go in order. For example 1, 2, 3... and 55, 56, 57... 3. Let the first number be x. As a result the second number will be x + 1, and the third number will be x + 2. 4. Since the sum of the numbers is 195, set up an equation that adds these numbers together and equals 195. x + (x + 1) + (x + 2) = 195 5. Simplify. (combine like terms) 3x + 3 = 195 6. Solve the equation for the variable. (do opposite operations to both sides till the variable is all by itself on one side) 3x = 192 (subtracted 3 from both sides) x = 64 (divide both sides by 3) 7. Since x = 64, the first consecutive number is 64, the second is 65, and the third is 66. (because they all go in order) *Check your solution by adding the numbers to make sure their sum is 195. 64 + 65 + 66 = 195