1, 2, 4, 41, 82, and 164
164 is divisible by 1, 2, 4, 41, 82, and 164.
The least common multiple of the numbers 12 and 164 is 492.
51 goes into 164 3 times with remainder 11.
171 / <unknown> = <some number> remainder 7 First, 171-7=164 Purpose: all factors of 164 would be either <unknown> or <some number> 164= 1 x 164 2 x 83 Factors of 164: 1, 2, 83, 164 Since you wanted two digit numbers, the only answer is 83. Proof: 171 / 83 = 2 R 7 * * * * * The last time I checked, 2*83 was not 164, but 2 times 82 was. So, the correct answers are 82 and 41.
4, 82, 164 are the composite factors of 164.
To determine how many times 4 goes into 164, we divide 164 by 4. The result is 41, with no remainder. Therefore, 4 goes into 164 exactly 41 times.
1, 2, 4, 41, 82, and 164
164 is divisible by 1, 2, 4, 41, 82, and 164.
The least common multiple of the numbers 12 and 164 is 492.
4 goes into 164 41 times.
51 goes into 164 3 times with remainder 11.
The Mathematical pyramid dividend of 164 is 25 which goes into 164 six (6) times.
163, 164, 165 let the three consecutive numbers be (n-1), n & (n+1). Then: (n-1) + n + (n+1) = 492 ⇒ 3n = 492 ⇒ n = 164 ⇒ the three numbers are 164-1 = 163, 164 & 164+1 = 165.
Factors of 164 in pairs: 1 x 164, 2 x 82, 4 x 41.
seven which are 146 164 416 461 614 641
No 150 = 3 x 50 164 - 150 = 14 so as the 14 remaining is not divisible by 3 then neither is 164