9, 21, 33, 45, 57 ,69, ... look at the pattern
3*3 = 9
3 *(3+4) = 3*7 = 21
3 *(7+4) = 3*11 = 33
3*(11+4) = 3*15 = 45
3*(15+4) = 3*19 = 57
3*(19+4) = 3*23 = 69
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Since the remainder is 0 when the numbers are divided by 3, then that number is a multiples of 3. For example, 45/3 = 15 remainder 0 45/4= 11 remainder 1 45/7 = 6 remainder 3
2
58
No. It is an even number, because it is divisible by 2. "Odd" numbers give you a non-zero remainder after you divide by 2. "Even" numbers give you a remainder of 0, after you divide by 2. 332 divided by 2 is 166 with a remainder of 0, so it is "even". But 333 divided by two is 166 with a remainder of 1, so it is "odd".
49 can be divided by these numbers without leaving a remainder: 1 7 and 49.
Since the remainder is 0 when the numbers are divided by 3, then that number is a multiples of 3. For example, 45/3 = 15 remainder 0 45/4= 11 remainder 1 45/7 = 6 remainder 3
2
58
1 can be divided into both numbers with no remainder
No. It is an even number, because it is divisible by 2. "Odd" numbers give you a non-zero remainder after you divide by 2. "Even" numbers give you a remainder of 0, after you divide by 2. 332 divided by 2 is 166 with a remainder of 0, so it is "even". But 333 divided by two is 166 with a remainder of 1, so it is "odd".
The remainder is 0.If A has a remainder of 1 when divided by 3, then A = 3m + 1 for some integer mIf B has a remainder of 2 when divided by 3, then B = 3n + 1 for some integer n→ A + B = (3m + 1) + (3n + 2)= 3m + 3n + 1 + 2= 3m + 3n + 3= 3(m + n + 1)= 3k where k = m + n + 1 and is an integer→ A + B = 3k + 0→ remainder when A + B divided by 3 is 0-------------------------------------------------------------------------From this, you may be able to see that:if A when divided by C has remainder Ra; andif B when divided by C has remainder Rb; then(A + B) divided by C will have remainder equal to the remainder of (Ra + Rb) divided by C
49 can be divided by these numbers without leaving a remainder: 1 7 and 49.
931 divided by 931 equals 1 with a remainder of 0. All multiples of 931 can be divided by 931 leaving no remainder.
0.25
They are the numbers that when divided by 2 leave a remainder of 1
0.027
26,51,76,101,126,151