They are: 1*2*3 = 6
There are 192.
420
456, 546 and 564 are three of the four possible even numbers.
6 if all digits are different, 27 otherwise.
They are: 1*2*3 = 6
There are 192.
420
456, 546 and 564 are three of the four possible even numbers.
6 if all digits are different, 27 otherwise.
To find the fraction of 4-digit natural numbers with a product of their digits that is even, we first need to determine the total number of 4-digit natural numbers. There are 9000 such numbers (from 1000 to 9999). Next, we consider the conditions for the product of digits to be even. For a number to have an even product of digits, at least one of the digits must be even. There are 5 even digits (0, 2, 4, 6, 8) and 5 odd digits (1, 3, 5, 7, 9). Therefore, the fraction of 4-digit natural numbers with an even product of digits is 5/10 * 9/10 * 9/10 * 9/10 = 3645/9000 = 809/2000.
The prime numbers 2 and 3 have 6 as their product when multiplied.
You can make 24 numbers by rearranging the digits. However, you can make vastly more if you allow mathematical operations on the digits. For example, 3+5*8-6 = 37.
Without repeating digits (not digets!) and without leading 0s, 600 of them.
Using the digits, we can make 81 x 62 equals 5022, which is the largest possible product.
The product of 5 x 6 x 7 is 210.
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.