let this integer be (xy)
(xy) = 10x + y
10x+y = 2.x.y
10x + y - 2xy = 0
2x.(5-y) +y= 0
x= y / 2(y-5)
when the integer provides this condition, it is equal to twice the product of its digits.
And there is such only one integer.
36
They are: 1*2*3 = 6
There are 192.
420
You can make three even numbers out of the digits 4, 5, and 6 by using the digits 4 and 6 twice: 464, 466, and 446.
6 if all digits are different, 27 otherwise.
They are: 1*2*3 = 6
There are 192.
420
You can make three even numbers out of the digits 4, 5, and 6 by using the digits 4 and 6 twice: 464, 466, and 446.
6 if all digits are different, 27 otherwise.
You can make 4*4*4 = 64 numbers.
You can make 24 numbers by rearranging the digits. However, you can make vastly more if you allow mathematical operations on the digits. For example, 3+5*8-6 = 37.
The prime numbers 2 and 3 have 6 as their product when multiplied.
Without repeating digits (not digets!) and without leading 0s, 600 of them.
Using the digits, we can make 81 x 62 equals 5022, which is the largest possible product.
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
Count the numbers of digits after the decimal points (DP) in the two numbers.Add these numbers together.Calculate the product, including any trailing 0s.Place the DP so that the number of digits after the DP is the same as the sum of the digits after the DP (step 2).Thus, for 15.38 * 0.0045The first number has 2 digits after the DP, the second has 4, so sum of digits after DP is 2+4 = 6.1538*0045 = 69210.The answer must have 6 digits after the DP so you need to insert a 0 after the DP to make it .069210 which can then be simplified to .06921