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Is this exactly how the problem was written?
Their sum is three times the middle number.
This is an algebraic expression. It can be written as 3(2x + 4)
Three consecutive whole numbers can be written as x, x + 1 and x + 2. Added together, their sum can be written as 3x + 3. Not only is that sum divisible by three, but by doing so [3(x + 1)] you can see that the sum is also equal to three times the second number.
No, the sum could be a whole number. 1 and 2/3 + 3 and 1/3 = 5