Is this exactly how the problem was written?
Their sum is three times the middle number.
This is an algebraic expression. It can be written as 3(2x + 4)
Three consecutive whole numbers can be written as x, x + 1 and x + 2. Added together, their sum can be written as 3x + 3. Not only is that sum divisible by three, but by doing so [3(x + 1)] you can see that the sum is also equal to three times the second number.
No, the sum could be a whole number. 1 and 2/3 + 3 and 1/3 = 5
Is this exactly how the problem was written?
Their sum is three times the middle number.
This is an algebraic expression. It can be written as 3(2x + 4)
Three consecutive whole numbers can be written as x, x + 1 and x + 2. Added together, their sum can be written as 3x + 3. Not only is that sum divisible by three, but by doing so [3(x + 1)] you can see that the sum is also equal to three times the second number.
The sum of three consecutive integers is -72
The sum of three times a number and its square is 10 more than 6 times a number?
No, the sum could be a whole number. 1 and 2/3 + 3 and 1/3 = 5
you get the sum and times with the subject total and times
Statement:The sum of three times of a number and five.Assumption:Let us take the number be x.So, Three times the number = 3x.Equation: 3x+5
The algebraic expression for the sum of 11 times 5 and three is 11s+3
if the sum of three is six then it would be 30 right?? i think depends on wat sum of 3 is
"The sum of a number and three times another number is 18. find the numbers if their product is a maximum?"