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Three consecutive whole numbers can be written as x, x + 1 and x + 2. Added together, their sum can be written as 3x + 3. Not only is that sum divisible by three, but by doing so [3(x + 1)] you can see that the sum is also equal to three times the second number.

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Q: Is the sum of 3 consecutive whole numbers always divisible by 3. Explain?
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