The use of the word "other" in the question implies that you already know of one or more situations where you can apply sss congruence. However, you have chosen not to share that information. Being unable to read minds over the internet, I do not know if my answer will refer to a situation that you already know or if it will be an "other" situation. I cannot, therefore, answer the question.
there are 4 types of congruence theorem-: ASA,SSS,RHS,SAS
true
No, the side-side-angle in congruence shortcut DOESN'T exist..hint-SSA turns backward--->ASS<---thats the problem of no word will come on math..kinda funny to laugh about but SSA=GET rid off it! use SSS, SAS, ASA, SAA, SSS, and AAA.
SSS, SAS, ASA, AAS, RHS. SSA can prove congruence if the angle in question is obtuse (if it's 90 degrees, then it's exactly equivalent to RHS).
No. You must know all three sides to apply SSS. If you only know two sides, you would have to go with SAS (which requires you to know the angle between those two sides as well).
there are 4 types of congruence theorem-: ASA,SSS,RHS,SAS
the congruence theorems or postulates are: SAS AAS SSS ASA
sss is when the 3 sides are congruent. all 3 angles are congruent
SSS
SSS is enough to show congruence.
Congruent - SSS
no sss and sas do
It is a special case of:the 3 sides (SSS) congruence, using Pythagoras,the 2 sides and included angle (SAS) congruence, using the sine rule.
true
No, the side-side-angle in congruence shortcut DOESN'T exist..hint-SSA turns backward--->ASS<---thats the problem of no word will come on math..kinda funny to laugh about but SSA=GET rid off it! use SSS, SAS, ASA, SAA, SSS, and AAA.
Here is the answer to your query. Consider two ∆ABC and ∆PQR. In these two triangles ∠B = ∠Q = 90�, AB = PQ and AC = PR. We can prove the R.H.S congruence rule i.e. to prove ∆ABC ≅ ∆PQR We need the help of SSS congruence rule. We have AB = PQ, and AC = PR So, to prove ∆ABC ≅ ∆PQR in SSS congruence rule we just need to show BC = QR Now, using Pythagoras theorems in ∆ABC and ∆PQR Now, in ∆ABC and ∆PQR AB = PQ, BC = QR, AC = PR ∴ ∆ABC ≅ ∆PQR [Using SSS congruence rule] So, we have AB = PQ, AC = PR, ∠B = ∠Q = 90� and we have proved ∆ABC ≅ ∆PQR. This is proof of R.H.S. congruence rule. Hope! This will help you. Cheers!!!
The correct answer is the AAS theorem