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The domain is the possible values that can be input into the function and produce a real number output.
The domain of a function represents the set of x values and the range represents the set of y values. Since y=x, the domain is the same as the range. In this case, they both are the set of all real numbers.
Domain measures X values. Since X isn't restricted by square roots or in the denominator the domain is all real numbers. Range measures Y values. Since X can be anything Y can be anything.
It could be a subset: for example, for the function y = log(x), the domain is x > 0. There are many functions whose domain is the complex plane.
No. You can always "cheat" to prove this by simply giving the function's domain a bound.Ex: f: [0,1] --> RI simply defined the function to have a bounded domain from 0 to 1 mapping to the codomain of the set of real numbers. The function itself can be almost anything, periodic or not.Another way to "cheat" is to simply recognize that all functions having a domain of R are bounded functions, by definition, in the complex plane, C.(Technically, you would say a non-compact Hermitian symmetric space has a bounded domain in a complex vector space.) Obviously, those functions include non-periodic functions as well.