0
What else can I help you with?
6 10 is a fraction how do I round it and write about 0 about 1 2 or about 1?
0 = 0/10, 1/2 = 5/10 and 1 = 10/10 so 6/10 is nearest to 5/10 or 1/2.
How do you write100 in exponentail notation?
100 = (1 x 10^2) + (0 x 10^1) + (0 x 10^0) or 1 x 10^2
What is 2 to the power of 0 times 10 the power of the 0?
Any value raised to the power 'zero'(0) equals '1'. Hence 2^(0) = 1 10 ^(0) = 1 Hence 2^(0) X 10^(0) = 1 x 1 = 1 the answer.
How do you write 73 in base 2?
(73)10 = (1 0 0 1 0 0 1)2
Can you write 12500000 in expanded form?
(1 x 10^7) + (2 x 10^6) + (5 x 10^5) + (0 x 10^4) + (0 x 10^3) + (0 x 10^2) + (0 x 10^1) + (0 x 10^0)(1 x 10000000) + (2 x 1000000) + (5 x 100000) + (0 x 10000) + (0 x 1000) + (0 x 100) + (0 x 10) + (0 x 1)
6 10 is a fraction how do I round it and write about 0 about 1 2 or about 1?
0 = 0/10, 1/2 = 5/10 and 1 = 10/10 so 6/10 is nearest to 5/10 or 1/2.
How do you write100 in exponentail notation?
100 = (1 x 10^2) + (0 x 10^1) + (0 x 10^0) or 1 x 10^2
What is 2 to the power of 0 times 10 the power of the 0?
Any value raised to the power 'zero'(0) equals '1'. Hence 2^(0) = 1 10 ^(0) = 1 Hence 2^(0) X 10^(0) = 1 x 1 = 1 the answer.
What does 400 plus 10 look like in expanded notation?
[(4 * 10^2) + (0 * 10^1) + (0 * 10^0)] + [(1 * 10^1) + (0 * 10^0)]
How do you write 21000 in expanded form?
21000 = (2 x 10000) + (1 x 1000) + (0 x 100) + (0 x 10) + (0 x 1) OR (2 x 10^4) + (1 x 10^3) + (0 x 10^2) + (0 x 10^1) + (0 x 10^0)
How do you write 73 in base 2?
(73)10 = (1 0 0 1 0 0 1)2
How do you find the decimal equivalent of binary 1101?
In the decimal system, the places are 10^0 (1), 10^1 (10), 10^2 (100), and 10^3 (1000) In the binary system, the places are 2^0 (1), 2^1 (2), 2^2 (4), and 2^3 (8) 1101 has one 1, one 4 and one 8. That makes 13, base ten.
How do you write 100203 in expanded form?
100,203 in expanded form is (1 x 100000) + (0 x 10000) + (0 x 1000) + (2 x 100) + (0 x 10) + (3 x 1)(1x1,000)+(2x3) or (1 x 10^5) + (0 x 10^4) + (0 x 10^3) + (2 x 10^2) + (0 x 10^1) + (3 x 10^0)100000 + 200 + 3
The vector representation of a convolutional code is g1=[1 1]and g2=[1 0]. If the received sequence is 11 11 01 10, please use Viterbi Algorithm to decode it. Please show the full trellis diagram, including the updated trellis state metrics?
The vector representation of a convolutional code is g1=[1 1] and g2=[1 0]. If the received sequence is 11 11 01 10, we can use Viterbi Algorithm to decode it. The full trellis diagram, including the updated trellis state metrics, is shown below: Time t1: State 0 (00): Metric = 0 State 1 (10): Metric = 0 Time t2: State 0 (00): Metric = 0 + (1-1)^2 + (1-1)^2 = 0 State 1 (10): Metric = 0 + (1-1)^2 + (1-0)^2 = 1 Time t3: State 0 (00): Metric = 0 + (1-1)^2 + (1-1)^2 = 0 State 1 (10): Metric = 1 + (1-1)^2 + (1-0)^2 = 2 State 0 (01): Metric = 0 + (1-1)^2 + (0-1)^2 = 1 State 1 (11): Metric = 0 + (1-1)^2 + (0-0)^2 = 0 Time t4: State 0 (00): Metric = 0 + (1-1)^2 + (1-1)^2 = 0 State 1 (10): Metric = 2 + (1-1)^2 + (1-0)^2 = 3 State 0 (01): Metric = 1 + (1-1)^2 + (0-1)^2 = 2 State 1 (11): Metric = 0 + (1-1)^2 + (0-0)^2 = 0 Therefore, the decoded sequence is 11 11 01 10.
How many ways can you make change for a 50 dollar bill using 10 5 and 20 dollar bills?
There are 12 ways to make change for a 50 dollar bill using 5, 10's and 20's. $20's $10's $5's 2 1 0 2 0 2 1 3 0 1 2 2 1 1 4 1 0 6 0 5 0 0 4 2 0 3 4 0 2 6 0 1 8 0 0 10
Can you write 12500000 in expanded form?
(1 x 10^7) + (2 x 10^6) + (5 x 10^5) + (0 x 10^4) + (0 x 10^3) + (0 x 10^2) + (0 x 10^1) + (0 x 10^0)(1 x 10000000) + (2 x 1000000) + (5 x 100000) + (0 x 10000) + (0 x 1000) + (0 x 100) + (0 x 10) + (0 x 1)
What is 67102200 in expanded form?
(6 x 10^7) + (7 x 10^6) + (1 x 10^5) + (0 x 10^4) + (2 x 10^3) + (2 x 10^2) + (0 x 10^1) + (0 x 10^0)
