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In the decimal system, the places are 10^0 (1), 10^1 (10), 10^2 (100), and 10^3 (1000)

In the binary system, the places are 2^0 (1), 2^1 (2), 2^2 (4), and 2^3 (8)

1101 has one 1, one 4 and one 8. That makes 13, base ten.

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βˆ™ 8y ago
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βˆ™ 10y ago

It is 1*2^3 + 1*2^2 + 0*2^1 + 1*2^0 = 8 + 4 + 0 + 1 = 13.

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Q: How do you find the decimal equivalent of binary 1101?
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Which is the following represents the binary equivalent of the decimal number 23?

The binary equivalent of the decimal number 23 is 10111. You can use an online converter to easily find this solution.


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To find the decimal equivalent of an 8-bit binary number, you can use the positional numbering system. Each bit in the binary number represents a power of 2, from right to left. Starting from the rightmost bit, you assign a value of 2^0, 2^1, 2^2, and so on, doubling the value for each position. Then, you sum up the values of the positions where the binary digit is 1. This sum is the decimal equivalent of the 8-bit binary number.


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To find the sum of binary numbers 1101 and 1110, we perform binary addition. Starting from the rightmost bit, we add each pair of bits along with the carry from the previous addition. 1+0 gives 1, 0+1 gives 1, 1+1 gives 0 with a carry of 1, and 1+1 (including the carry) gives 1 with a carry of 1. Therefore, the sum of 1101 and 1110 in binary is 11011.


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