7 yd 1 ft - 5 yd 2 ft = 22 ft - 17 ft = 5 ft = 1 yd 2 ft.
1 yard = 3 feet. So 9 yd 7 ft - 6 yd 8 ft = 2 yd 2ft
3 ft = 1 yd 36 in = 1 yd ⇒ 50 ft x 7 ft x 4 in = (50 ÷ 3) yd x (7 ÷ 3) yd x (4 ÷ 36) yd = 350/81 cu yd = 426/81 cu yd ≈ 4.321 cu yd
7 yd = 21 ft
7 feet are 21 yards. Answer: 2.33 yd Algebraic Steps / Dimensional Analysis7 ft*1 yd 3 ft=2.333333333 yd
Which is greater? 21 ft or 7 yd
7 yd 1 ft - 5 yd 2 ft = 22 ft - 17 ft = 5 ft = 1 yd 2 ft.
1 yard = 3 feet. So 9 yd 7 ft - 6 yd 8 ft = 2 yd 2ft
3 ft = 1 yd 36 in = 1 yd ⇒ 50 ft x 7 ft x 4 in = (50 ÷ 3) yd x (7 ÷ 3) yd x (4 ÷ 36) yd = 350/81 cu yd = 426/81 cu yd ≈ 4.321 cu yd
7 yd = 21 ft
1 ft = 12 in 36 in = 1 yd → 7 ft 7 in = 7 x 12 + 7 in = 91 in → 91 in = 91 / 36 yd = 2 yd 19/36 in ≈ 2.53 yd
25 feet- a yard(yd) is 3 feet.
Assuming that the warehouse is a cuboid with flat walls and that the storage shelves also need to be heated, then: 3 ft = 1 yd volume = 200 ft × 400 ft × 20 ft = (200 ÷ 3) yd × (400 ÷ 3) yd × (20 ÷ 3) yd = 1600000/27 cu yd = 59,259 7/27 cu yd ≈ 59,259 cu yards (at that size, the fraction is immaterial; it is also reasonable to round to the nearest 10 cu yd to give approx 59,260 cu yd.)
7 feet are 21 yards. Answer: 2.33 yd Algebraic Steps / Dimensional Analysis7 ft*1 yd 3 ft=2.333333333 yd
3 yd = 1 ft → volume = 120 ft × 40 ft × 1 ft = (120 ÷ 3) yd × (40 ÷ 3) yd × (1 ÷ 3) yd = 4800 ÷ 27 yd³ = 177 7/9 cu yd ≈ 177.78 cubic yards.
23 feet
5yd 3ft