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It depends on the specific test.

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15y ago

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What is the average score between 79 82 93 91 and100?

79+82+93+91+100=445/5=89


If the numbers 79 86 81 80 89 are on a test what number is needed to get a mean of 84?

To find the number needed to achieve a mean of 84 with the existing scores of 79, 86, 81, 80, and 89, first calculate the current total of the scores, which is 415. Since there are 5 scores, let ( x ) be the score needed to reach the desired mean with 6 scores. The equation is ((415 + x)/6 = 84). Solving this gives ( 415 + x = 504), so ( x = 504 - 415 = 89). Thus, you would need a score of 89.


Which statistic is misleading in the following set of test scores 2 85 87 88 89 A. upper quartile B. mode C. mean D. median?

The statistic that is misleading in this set of test scores is the mean (C). The mean is calculated as (2 + 85 + 87 + 88 + 89) / 5 = 50.2, which does not accurately represent the overall performance of the students due to the outlier score of 2. In contrast, the median (88) and mode (85) provide a better indication of the central tendency of the majority of the scores.


If you have a score of 95 89 91 and 93 what score must you get on your final test to raise your average to 93?

95,89,91, 93 ,x. Are the five scores , 'x' being unknown and to find. Hence (95 + 89 + 91 + 93 + x) / 5 = 93 Add the four known values. (368 + x) / 5 = 93 Multiply both sides by '5' 368 + x = 465 Subtract '368' from both sides x = 97 So you must score '97' in your final test to bring your mean/average to '93'.


What is the answer to 89 times 56 plus 89?

(89)56 +89 = 5073