A hexagon and a triangle.
a hexagon
Thirteen separte hexagons have 13x6 sides, or 78 sides. However, it's possible that they have shared borders, so then there would be fewer because you wouldn't count the same side twice if it was shared.
square
In the case of polygons (basically the simplest case), you need to determine that corresponding sides are proportional (for example, all sides in figure "B" are twice as large as the corresponding sides in figure "A"), and that corresponding angles are equal.
11 sides The diagonal of a polygon is a line segment that joins two non adjacent vertices. So for a n-sided polygon, each vertex can be joined to n-3 other sides. So there ought to be n x (n-3) diagonals for a n-sided polygon; however, each diagonal is counted twice, once by the vertex at each end. So the number of diagonals is: diagonals = n (n-3) / 2 So for 44 diagonals: 44 = n (n-3) / 2 88 = n2 - 3n n2 - 3n - 88 = 0 (n - 11)(n + 8) = 0 n = 11 or -8 Since the number of sides can't be negative, the number of sides is 11, a hendecagon (or undecagon)
hexagon
a hexagon ( triangle has 3 and a hexagon has 6)
A 7 sided polygon has 14 diagonals
octagon-8 sides
An heptagon has 7 sides and 14 diagonals
a hexagon
A regular hexagon
A regular hexagon
In a polygon with n sides, we have n(n-3)/2 diagonals. In a convex polygon with n sides, you can draw n-3 diagonals from each vertex, but you are counting each one twice you so you need to divide by do. That is why we have n(n-3) divided by 2
the polygon would be a square
Thirteen separte hexagons have 13x6 sides, or 78 sides. However, it's possible that they have shared borders, so then there would be fewer because you wouldn't count the same side twice if it was shared.
sum of exterior angles in a polygon is always equal to 3600,sum of all the interior angles is given by (n-2)1800, where n is the number of sides of the polygon.According to the question,(n-2)1800=2(3600)n-2=4so n=6answer:6