To find the zeros of the polynomial from the given graph, identify the points where the graph intersects the x-axis. These intersection points represent the values of x for which the polynomial equals zero. If the graph crosses the x-axis at specific points, those x-values are the zeros of the polynomial. If the graph merely touches the x-axis without crossing, those points indicate repeated zeros.
The equation for the given points is y = x+4 in slope intercept form
The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.
There can be no minimum number - it is simply not possible. Given any n points in 3-dimensional space, it is possible to find a polynomial that will generate a curve going through each of those points. There are other functions which will also do the trick. So, given any number of points, it would be impossible to determine whether they were generated by a fractal or a polynomial (or other function).
There is no minimum number - it is simply not possible. Given any n points in 2-dimensional space, it is possible to find a polynomial of order (n-1) that will generate a curve going through each of those points. There are other functions which will also do the trick. So, given any number of points, it would be impossible to determine whether they were generated by a fractal or a polynomial (or other function).
The slope of a line that passes through two points is (difference in y) / (difference in x).
To find the zeros of the polynomial from the given graph, identify the points where the graph intersects the x-axis. These intersection points represent the values of x for which the polynomial equals zero. If the graph crosses the x-axis at specific points, those x-values are the zeros of the polynomial. If the graph merely touches the x-axis without crossing, those points indicate repeated zeros.
There are an infinite number of planes that pass through a pair of points. Select any plane that passes through both the points and then rotate it along the line joining the two points.
The equation for the given points is y = x+4 in slope intercept form
Yes. In fact, given any three non-collinear points, there is one (and only one) circle that passes through all three points.
The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.
Since no polynomial was given, no answer will be given.
There can be no minimum number - it is simply not possible. Given any n points in 3-dimensional space, it is possible to find a polynomial that will generate a curve going through each of those points. There are other functions which will also do the trick. So, given any number of points, it would be impossible to determine whether they were generated by a fractal or a polynomial (or other function).
You haven't given points, you've just given single values. for there to be a point in a plane, you need 2 coordinates, both x and y
There is no minimum number - it is simply not possible. Given any n points in 2-dimensional space, it is possible to find a polynomial of order (n-1) that will generate a curve going through each of those points. There are other functions which will also do the trick. So, given any number of points, it would be impossible to determine whether they were generated by a fractal or a polynomial (or other function).
It's not possible because the given points would be a vertical line parallel to the y axis
If you mean: y = 5x then it has a slope of 5 and passes through the origin of (0, 0)