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The equation for the given points is y = x+4 in slope intercept form
The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.
There can be no minimum number - it is simply not possible. Given any n points in 3-dimensional space, it is possible to find a polynomial that will generate a curve going through each of those points. There are other functions which will also do the trick. So, given any number of points, it would be impossible to determine whether they were generated by a fractal or a polynomial (or other function).
There is no minimum number - it is simply not possible. Given any n points in 2-dimensional space, it is possible to find a polynomial of order (n-1) that will generate a curve going through each of those points. There are other functions which will also do the trick. So, given any number of points, it would be impossible to determine whether they were generated by a fractal or a polynomial (or other function).
It could be any number you like.Given any fifth number it is easy to find a quartic polynomial (of degree 4) such that is passes through the given four points and the new one. Each choice of the fifth number will result in a different polynomial. So, since there are infinitely many choices for the fifth number, there are infinitely many position to value rules. In addition, there are non-polynomial functions as well.The simplest answer is, perhaps, the cubic, Un = n3 - 9n2 + 32n - 10 for n = 1, 2, 3, ...
The slope of a line that passes through two points is (difference in y) / (difference in x).
There are an infinite number of planes that pass through a pair of points. Select any plane that passes through both the points and then rotate it along the line joining the two points.
The equation for the given points is y = x+4 in slope intercept form
Yes. In fact, given any three non-collinear points, there is one (and only one) circle that passes through all three points.
The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.The answer depends on where, in the sequence, the missing number is meant to go.Furthermore, whatever number you choose and wherever in the sequence it is meant to be, it is always possible to find a polynomial of degree 5 that will go through all five points given in the question and your chosen one.Using a polynomial of degree 4, the next number is -218.
There can be no minimum number - it is simply not possible. Given any n points in 3-dimensional space, it is possible to find a polynomial that will generate a curve going through each of those points. There are other functions which will also do the trick. So, given any number of points, it would be impossible to determine whether they were generated by a fractal or a polynomial (or other function).
Since no polynomial was given, no answer will be given.
You haven't given points, you've just given single values. for there to be a point in a plane, you need 2 coordinates, both x and y
There is no minimum number - it is simply not possible. Given any n points in 2-dimensional space, it is possible to find a polynomial of order (n-1) that will generate a curve going through each of those points. There are other functions which will also do the trick. So, given any number of points, it would be impossible to determine whether they were generated by a fractal or a polynomial (or other function).
It's not possible because the given points would be a vertical line parallel to the y axis
There are many possible answers. But given 5 points, an answer that can be guaranteed is that it is a polynomial of degree 4 (a quartic).In this case, Un = (-13n4 + 166n3 - 719n2 + 1310n - 720)/24There are many possible answers. But given 5 points, an answer that can be guaranteed is that it is a polynomial of degree 4 (a quartic).In this case, Un = (-13n4 + 166n3 - 719n2 + 1310n - 720)/24There are many possible answers. But given 5 points, an answer that can be guaranteed is that it is a polynomial of degree 4 (a quartic).In this case, Un = (-13n4 + 166n3 - 719n2 + 1310n - 720)/24There are many possible answers. But given 5 points, an answer that can be guaranteed is that it is a polynomial of degree 4 (a quartic).In this case, Un = (-13n4 + 166n3 - 719n2 + 1310n - 720)/24
It could be any number you like.Given any fifth number it is easy to find a quartic polynomial (of degree 4) such that is passes through the given four points and the new one. Each choice of the fifth number will result in a different polynomial. So, since there are infinitely many choices for the fifth number, there are infinitely many position to value rules. In addition, there are non-polynomial functions as well.The simplest answer is, perhaps, the cubic, Un = n3 - 9n2 + 32n - 10 for n = 1, 2, 3, ...