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It's not possible because the given points would be a vertical line parallel to the y axis

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Q: Find the slope of the line that passes through these points 3 6 and 3 5?

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To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).

m= (y2 - y1)/(x2 - x1) m= (4 - 0)/(2 - 0) m = 2

Since the line is horizontal, the slope is zero.

Points: (0, 0) and (7, -t) Slope: -3/5 Slope = 0--t/0-7 = -3/5 - t/7 = -3/5 Multiply both sides by -7: t = 21/5 or 4.2

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y=mx+b

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No

2

1

2222

Not always. For example, try to find the slope of the line that passes through the points (3, 4) and (2, 3).

It is a straight line with no slope with a 'y' intercept of 2

Slope, m, equals (y2-y1)/(x2-x1). Slope is (8-2)/(8-2) or 1.

Another set of points are needed to find the slope.

Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.

The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.

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