There are no 3-digit whole numbers whose digits sum to 3. The smallest 3-digit number is 100, and the largest is 999, but in neither case is the sum of the digits equal to 3.
If you mean 3-digit numbers whose digits are in decreasing order, then the answer is 20.
solution: we know that there are 25 prime numbers are between 1-100 and 168 prime numbers less than 1000. 100 x 100=10000(5 digits) 999 x 999=998001(6 digits) 1000 x 1000=1000000(7 digits) so our answer should be same as the number of prime numbers between 100 to 999. hence, 168-25=143. 143 prime numbers will be there less than 1000 whose square has 5 or 6 digits.
100
20 and 100.GCF is 20, and LCM is 100.
10
There are no 3-digit whole numbers whose digits sum to 3. The smallest 3-digit number is 100, and the largest is 999, but in neither case is the sum of the digits equal to 3.
If you mean 3-digit numbers whose digits are in decreasing order, then the answer is 20.
solution: we know that there are 25 prime numbers are between 1-100 and 168 prime numbers less than 1000. 100 x 100=10000(5 digits) 999 x 999=998001(6 digits) 1000 x 1000=1000000(7 digits) so our answer should be same as the number of prime numbers between 100 to 999. hence, 168-25=143. 143 prime numbers will be there less than 1000 whose square has 5 or 6 digits.
There are four pair of mirror primes.
525
-99
There are nine(9) numbers: 19, 28, 37, 46, 55, 64, 73, 82, 91
Mirror primes are pairs of prime numbers whose digits are reversed. (13,31)(17,71)(37,73)(79,97)
Since we are talking for the sum of digits, then we are talking about 2-digit numbers between 1 and 100, which are 90 numbers (10 to 99). From these numbers only half of them satisfy the above condition, that is 45 numbers. So 50% of 2-digit numbers between 1 and 100 have an odd sum of their digits.
100
20 and 100.GCF is 20, and LCM is 100.